YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(a(b(b(b(b(x1)))))) -> a(b(b(b(b(b(a(x1))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(b(b(a(b(x1)))))) -> a(b(b(b(b(b(a(x1))))))) Q is empty. ---------------------------------------- (3) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: b(b(b(b(a(b(x1)))))) -> a(b(b(b(b(b(a(x1))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76 Node 63 is start node and node 64 is final node. Those nodes are connected through the following edges: * 63 to 65 labelled a_1(0)* 64 to 64 labelled #_1(0)* 65 to 66 labelled b_1(0)* 66 to 67 labelled b_1(0)* 66 to 71 labelled a_1(1)* 67 to 68 labelled b_1(0)* 68 to 69 labelled b_1(0)* 69 to 70 labelled b_1(0)* 70 to 64 labelled a_1(0)* 71 to 72 labelled b_1(1)* 72 to 73 labelled b_1(1)* 72 to 71 labelled a_1(1)* 73 to 74 labelled b_1(1)* 74 to 75 labelled b_1(1)* 75 to 76 labelled b_1(1)* 76 to 64 labelled a_1(1) ---------------------------------------- (4) YES