YES

Problem:
 t(f(x1)) -> t(c(n(x1)))
 n(f(x1)) -> f(n(x1))
 o(f(x1)) -> f(o(x1))
 n(s(x1)) -> f(s(x1))
 o(s(x1)) -> f(s(x1))
 c(f(x1)) -> f(c(x1))
 c(n(x1)) -> n(c(x1))
 c(o(x1)) -> o(c(x1))
 c(o(x1)) -> o(x1)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [o](x0) = x0 + 8,
   
   [t](x0) = x0,
   
   [c](x0) = x0,
   
   [s](x0) = 8x0,
   
   [f](x0) = x0,
   
   [n](x0) = x0
  orientation:
   t(f(x1)) = x1 >= x1 = t(c(n(x1)))
   
   n(f(x1)) = x1 >= x1 = f(n(x1))
   
   o(f(x1)) = x1 + 8 >= x1 + 8 = f(o(x1))
   
   n(s(x1)) = 8x1 >= 8x1 = f(s(x1))
   
   o(s(x1)) = 8x1 + 8 >= 8x1 = f(s(x1))
   
   c(f(x1)) = x1 >= x1 = f(c(x1))
   
   c(n(x1)) = x1 >= x1 = n(c(x1))
   
   c(o(x1)) = x1 + 8 >= x1 + 8 = o(c(x1))
   
   c(o(x1)) = x1 + 8 >= x1 + 8 = o(x1)
  problem:
   t(f(x1)) -> t(c(n(x1)))
   n(f(x1)) -> f(n(x1))
   o(f(x1)) -> f(o(x1))
   n(s(x1)) -> f(s(x1))
   c(f(x1)) -> f(c(x1))
   c(n(x1)) -> n(c(x1))
   c(o(x1)) -> o(c(x1))
   c(o(x1)) -> o(x1)
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [o](x0) = 6x0 + 1,
    
    [t](x0) = 2x0 + 1,
    
    [c](x0) = x0,
    
    [s](x0) = x0 + 1,
    
    [f](x0) = 4x0 + 1,
    
    [n](x0) = 4x0 + 1
   orientation:
    t(f(x1)) = 8x1 + 3 >= 8x1 + 3 = t(c(n(x1)))
    
    n(f(x1)) = 16x1 + 5 >= 16x1 + 5 = f(n(x1))
    
    o(f(x1)) = 24x1 + 7 >= 24x1 + 5 = f(o(x1))
    
    n(s(x1)) = 4x1 + 5 >= 4x1 + 5 = f(s(x1))
    
    c(f(x1)) = 4x1 + 1 >= 4x1 + 1 = f(c(x1))
    
    c(n(x1)) = 4x1 + 1 >= 4x1 + 1 = n(c(x1))
    
    c(o(x1)) = 6x1 + 1 >= 6x1 + 1 = o(c(x1))
    
    c(o(x1)) = 6x1 + 1 >= 6x1 + 1 = o(x1)
   problem:
    t(f(x1)) -> t(c(n(x1)))
    n(f(x1)) -> f(n(x1))
    n(s(x1)) -> f(s(x1))
    c(f(x1)) -> f(c(x1))
    c(n(x1)) -> n(c(x1))
    c(o(x1)) -> o(c(x1))
    c(o(x1)) -> o(x1)
   Matrix Interpretation Processor: dim=3
    
    interpretation:
               [1 1 1]     [0]
     [o](x0) = [0 0 0]x0 + [0]
               [0 0 1]     [1],
     
               [1 0 0]     [0]
     [t](x0) = [0 0 1]x0 + [1]
               [0 0 0]     [0],
     
               [1 0 1]     [0]
     [c](x0) = [0 0 0]x0 + [1]
               [0 0 1]     [0],
     
               [1 0 1]     [0]
     [s](x0) = [1 1 1]x0 + [1]
               [0 0 0]     [0],
     
               [1 0 1]  
     [f](x0) = [0 0 0]x0
               [0 0 1]  ,
     
                 
     [n](x0) = x0
                 
    orientation:
                [1 0 1]     [0]    [1 0 1]     [0]              
     t(f(x1)) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = t(c(n(x1)))
                [0 0 0]     [0]    [0 0 0]     [0]              
     
                [1 0 1]      [1 0 1]             
     n(f(x1)) = [0 0 0]x1 >= [0 0 0]x1 = f(n(x1))
                [0 0 1]      [0 0 1]             
     
                [1 0 1]     [0]    [1 0 1]             
     n(s(x1)) = [1 1 1]x1 + [1] >= [0 0 0]x1 = f(s(x1))
                [0 0 0]     [0]    [0 0 0]             
     
                [1 0 2]     [0]    [1 0 2]             
     c(f(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = f(c(x1))
                [0 0 1]     [0]    [0 0 1]             
     
                [1 0 1]     [0]    [1 0 1]     [0]           
     c(n(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = n(c(x1))
                [0 0 1]     [0]    [0 0 1]     [0]           
     
                [1 1 2]     [1]    [1 0 2]     [1]           
     c(o(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [0] = o(c(x1))
                [0 0 1]     [1]    [0 0 1]     [1]           
     
                [1 1 2]     [1]    [1 1 1]     [0]        
     c(o(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [0] = o(x1)
                [0 0 1]     [1]    [0 0 1]     [1]        
    problem:
     t(f(x1)) -> t(c(n(x1)))
     n(f(x1)) -> f(n(x1))
     n(s(x1)) -> f(s(x1))
     c(f(x1)) -> f(c(x1))
     c(n(x1)) -> n(c(x1))
     c(o(x1)) -> o(c(x1))
    String Reversal Processor:
     f(t(x1)) -> n(c(t(x1)))
     f(n(x1)) -> n(f(x1))
     s(n(x1)) -> s(f(x1))
     f(c(x1)) -> c(f(x1))
     n(c(x1)) -> c(n(x1))
     o(c(x1)) -> c(o(x1))
     Matrix Interpretation Processor: dim=3
      
      interpretation:
                 [1 0 0]     [0]
       [o](x0) = [1 0 0]x0 + [1]
                 [0 0 0]     [0],
       
                 [1 0 0]     [0]
       [t](x0) = [1 0 0]x0 + [1]
                 [0 0 0]     [0],
       
                 [1 0 0]  
       [c](x0) = [0 0 0]x0
                 [0 0 0]  ,
       
                 [1 1 0]     [0]
       [s](x0) = [1 0 0]x0 + [0]
                 [1 1 0]     [1],
       
                 [1 0 0]     [0]
       [f](x0) = [0 1 0]x0 + [0]
                 [0 0 0]     [1],
       
                 [1 0 0]     [0]
       [n](x0) = [1 1 0]x0 + [1]
                 [0 0 0]     [1]
      orientation:
                  [1 0 0]     [0]    [1 0 0]     [0]              
       f(t(x1)) = [1 0 0]x1 + [1] >= [1 0 0]x1 + [1] = n(c(t(x1)))
                  [0 0 0]     [1]    [0 0 0]     [1]              
       
                  [1 0 0]     [0]    [1 0 0]     [0]           
       f(n(x1)) = [1 1 0]x1 + [1] >= [1 1 0]x1 + [1] = n(f(x1))
                  [0 0 0]     [1]    [0 0 0]     [1]           
       
                  [2 1 0]     [1]    [1 1 0]     [0]           
       s(n(x1)) = [1 0 0]x1 + [0] >= [1 0 0]x1 + [0] = s(f(x1))
                  [2 1 0]     [2]    [1 1 0]     [1]           
       
                  [1 0 0]     [0]    [1 0 0]             
       f(c(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 = c(f(x1))
                  [0 0 0]     [1]    [0 0 0]             
       
                  [1 0 0]     [0]    [1 0 0]             
       n(c(x1)) = [1 0 0]x1 + [1] >= [0 0 0]x1 = c(n(x1))
                  [0 0 0]     [1]    [0 0 0]             
       
                  [1 0 0]     [0]    [1 0 0]             
       o(c(x1)) = [1 0 0]x1 + [1] >= [0 0 0]x1 = c(o(x1))
                  [0 0 0]     [0]    [0 0 0]             
      problem:
       f(t(x1)) -> n(c(t(x1)))
       f(n(x1)) -> n(f(x1))
       f(c(x1)) -> c(f(x1))
       n(c(x1)) -> c(n(x1))
       o(c(x1)) -> c(o(x1))
      WPO Processor:
       algebra: Sum
       weight function:
        w0 = 0
        w(c) = w(t) = w(f) = 2
        w(o) = 1
        w(n) = 0
       status function:
        st(o) = st(c) = st(n) = st(t) = st(f) = [0]
       precedence:
        f > o ~ n > c ~ t
       problem:
        
       Qed