YES

Problem:
 b(a(b(c(c(b(x1)))))) -> a(b(b(c(c(b(a(x1)))))))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {4}
   transitions:
    a1(19) -> 20*
    a1(13) -> 14*
    c1(16) -> 17*
    c1(15) -> 16*
    b1(17) -> 18*
    b1(18) -> 19*
    b1(14) -> 15*
    b0(4) -> 4*
    c0(4) -> 4*
    a0(4) -> 4*
    4 -> 13*
    20 -> 15,4
  problem:
   
  Qed