YES

Problem:
 b(a(c(b(b(x1))))) -> a(c(b(b(b(a(c(x1)))))))

Proof:
 Bounds Processor:
  bound: 2
  enrichment: match
  automaton:
   final states: {4}
   transitions:
    a1(19) -> 20*
    a1(14) -> 15*
    b1(16) -> 17*
    b1(15) -> 16*
    b1(17) -> 18*
    c1(21) -> 22*
    c1(13) -> 14*
    c1(18) -> 19*
    b0(4) -> 4*
    c0(4) -> 4*
    a0(4) -> 4*
    a2(28) -> 29*
    a2(43) -> 44*
    a2(38) -> 39*
    a2(33) -> 34*
    b2(40) -> 41*
    b2(30) -> 31*
    b2(29) -> 30*
    b2(39) -> 40*
    b2(31) -> 32*
    b2(41) -> 42*
    c2(42) -> 43*
    c2(27) -> 28*
    c2(32) -> 33*
    c2(37) -> 38*
    30 -> 37*
    16 -> 27,21
    4 -> 13*
    22 -> 14*
    44 -> 18*
    20 -> 16,4
    34 -> 17*
  problem:
   
  Qed