YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 50 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 21 ms] (8) QDP (9) QDPOrderProof [EQUIVALENT, 92 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 253 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(d(d(x1)))) -> B(b(x1)) A(a(d(d(x1)))) -> B(x1) A(a(x1)) -> B(b(b(b(b(b(x1)))))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) A(a(x1)) -> B(x1) B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) B(b(d(d(b(b(x1)))))) -> C(c(x1)) B(b(d(d(b(b(x1)))))) -> C(x1) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) A(a(d(d(x1)))) -> B(b(x1)) B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) A(a(d(d(x1)))) -> B(x1) A(a(x1)) -> B(b(b(b(b(b(x1)))))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) A(a(x1)) -> B(x1) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(d(d(x1)))) -> B(b(x1)) A(a(d(d(x1)))) -> B(x1) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial interpretation [POLO]: POL(A(x_1)) = x_1 POL(B(x_1)) = x_1 POL(a(x_1)) = x_1 POL(b(x_1)) = x_1 POL(c(x_1)) = 1 + x_1 POL(d(x_1)) = 1 + x_1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(x1)) -> d(d(x1)) a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) A(a(x1)) -> B(b(b(b(b(b(x1)))))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) A(a(x1)) -> B(x1) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (7) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial interpretation [POLO]: POL(A(x_1)) = x_1 POL(B(x_1)) = 1 POL(a(x_1)) = 1 POL(b(x_1)) = 1 POL(c(x_1)) = 0 POL(d(x_1)) = 0 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(x1)) -> d(d(x1)) a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) ---------------------------------------- (8) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) A(a(x1)) -> B(b(b(b(b(b(x1)))))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) A(a(x1)) -> B(x1) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (9) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(x1)) -> B(x1) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation: POL( A_1(x_1) ) = max{0, 2x_1 - 1} POL( a_1(x_1) ) = x_1 + 1 POL( B_1(x_1) ) = max{0, x_1 - 1} POL( c_1(x_1) ) = 0 POL( d_1(x_1) ) = max{0, -2} POL( b_1(x_1) ) = 2 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(x1)) -> d(d(x1)) a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) ---------------------------------------- (10) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) A(a(x1)) -> B(b(b(b(b(b(x1)))))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (11) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) A(a(x1)) -> B(b(b(b(b(x1))))) A(a(x1)) -> B(b(b(b(x1)))) A(a(x1)) -> B(b(b(x1))) A(a(x1)) -> B(b(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial interpretation [POLO]: POL(A(x_1)) = 2*x_1 POL(B(x_1)) = 2*x_1 POL(a(x_1)) = 5 + x_1 POL(b(x_1)) = 1 + x_1 POL(c(x_1)) = 2*x_1 POL(d(x_1)) = 2*x_1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(x1)) -> d(d(x1)) a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) ---------------------------------------- (12) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(x1)) -> B(b(b(b(b(b(x1)))))) The TRS R consists of the following rules: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (13) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node. ---------------------------------------- (14) TRUE