YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 17 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 54 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 66 ms] (12) QDP (13) QDPOrderProof [EQUIVALENT, 60 ms] (14) QDP (15) PisEmptyProof [EQUIVALENT, 0 ms] (16) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(c(c(a(a(x1)))))) b(b(c(c(x1)))) -> c(c(b(b(b(b(x1)))))) a(a(c(c(x1)))) -> c(c(a(a(b(b(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(a(a(x1)))) -> C(c(b(b(x1)))) B(b(a(a(x1)))) -> C(b(b(x1))) B(b(a(a(x1)))) -> B(b(x1)) B(b(a(a(x1)))) -> B(x1) C(c(b(b(x1)))) -> B(b(b(b(c(c(x1)))))) C(c(b(b(x1)))) -> B(b(b(c(c(x1))))) C(c(b(b(x1)))) -> B(b(c(c(x1)))) C(c(b(b(x1)))) -> B(c(c(x1))) C(c(b(b(x1)))) -> C(c(x1)) C(c(b(b(x1)))) -> C(x1) C(c(a(a(x1)))) -> B(b(a(a(c(c(x1)))))) C(c(a(a(x1)))) -> B(a(a(c(c(x1))))) C(c(a(a(x1)))) -> C(c(x1)) C(c(a(a(x1)))) -> C(x1) The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: C(c(b(b(x1)))) -> B(b(b(b(c(c(x1)))))) B(b(a(a(x1)))) -> C(c(b(b(x1)))) C(c(b(b(x1)))) -> B(b(b(c(c(x1))))) B(b(a(a(x1)))) -> B(b(x1)) B(b(a(a(x1)))) -> B(x1) C(c(b(b(x1)))) -> B(b(c(c(x1)))) C(c(b(b(x1)))) -> B(c(c(x1))) C(c(b(b(x1)))) -> C(c(x1)) C(c(b(b(x1)))) -> C(x1) C(c(a(a(x1)))) -> B(b(a(a(c(c(x1)))))) C(c(a(a(x1)))) -> C(c(x1)) C(c(a(a(x1)))) -> C(x1) The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (7) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. B(b(a(a(x1)))) -> C(c(b(b(x1)))) B(b(a(a(x1)))) -> B(b(x1)) B(b(a(a(x1)))) -> B(x1) C(c(a(a(x1)))) -> C(c(x1)) C(c(a(a(x1)))) -> C(x1) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial interpretation [POLO]: POL(B(x_1)) = x_1 POL(C(x_1)) = x_1 POL(a(x_1)) = 1 + x_1 POL(b(x_1)) = x_1 POL(c(x_1)) = x_1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) ---------------------------------------- (8) Obligation: Q DP problem: The TRS P consists of the following rules: C(c(b(b(x1)))) -> B(b(b(b(c(c(x1)))))) C(c(b(b(x1)))) -> B(b(b(c(c(x1))))) C(c(b(b(x1)))) -> B(b(c(c(x1)))) C(c(b(b(x1)))) -> B(c(c(x1))) C(c(b(b(x1)))) -> C(c(x1)) C(c(b(b(x1)))) -> C(x1) C(c(a(a(x1)))) -> B(b(a(a(c(c(x1)))))) The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (9) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 5 less nodes. ---------------------------------------- (10) Obligation: Q DP problem: The TRS P consists of the following rules: C(c(b(b(x1)))) -> C(x1) C(c(b(b(x1)))) -> C(c(x1)) The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (11) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. C(c(b(b(x1)))) -> C(x1) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation: POL( C_1(x_1) ) = max{0, 2x_1 - 2} POL( c_1(x_1) ) = 2x_1 + 2 POL( b_1(x_1) ) = x_1 POL( a_1(x_1) ) = max{0, -2} The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) ---------------------------------------- (12) Obligation: Q DP problem: The TRS P consists of the following rules: C(c(b(b(x1)))) -> C(c(x1)) The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (13) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. C(c(b(b(x1)))) -> C(c(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation: POL( C_1(x_1) ) = max{0, x_1 - 2} POL( c_1(x_1) ) = 2x_1 POL( b_1(x_1) ) = x_1 + 1 POL( a_1(x_1) ) = 1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) ---------------------------------------- (14) Obligation: Q DP problem: P is empty. The TRS R consists of the following rules: b(b(a(a(x1)))) -> a(a(c(c(b(b(x1)))))) c(c(b(b(x1)))) -> b(b(b(b(c(c(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (15) PisEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R) chain. ---------------------------------------- (16) YES