YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 11 ms] (2) QDP (3) QDPOrderProof [EQUIVALENT, 198 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 99 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 49 ms] (8) QDP (9) PisEmptyProof [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(b(a(x1)))) -> A(a(b(a(b(b(x1)))))) A(b(b(a(x1)))) -> A(b(a(b(b(x1))))) A(b(b(a(x1)))) -> A(b(b(x1))) The TRS R consists of the following rules: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(b(b(a(x1)))) -> A(b(b(x1))) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[0A]] + [[0A, -I, 0A]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [-I], [-I]] + [[-I, -I, 0A], [-I, -I, -I], [-I, 0A, -I]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [1A], [0A]] + [[0A, 0A, -I], [1A, 1A, -I], [0A, 0A, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(b(a(x1)))) -> A(a(b(a(b(b(x1)))))) A(b(b(a(x1)))) -> A(b(a(b(b(x1))))) The TRS R consists of the following rules: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(b(b(a(x1)))) -> A(b(a(b(b(x1))))) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[0A]] + [[0A, -I, 0A]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, -I], [0A, -I, -I], [-I, 0A, -I]] * x_1 >>> <<< POL(a(x_1)) = [[1A], [0A], [0A]] + [[1A, -I, 1A], [0A, 0A, 0A], [0A, 0A, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(b(a(x1)))) -> A(a(b(a(b(b(x1)))))) The TRS R consists of the following rules: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (7) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(b(b(a(x1)))) -> A(a(b(a(b(b(x1)))))) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[-I]] + [[0A, -I, -I]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, 0A], [-I, -I, -I], [-I, 0A, -I]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [1A], [-I]] + [[0A, 0A, -I], [1A, 1A, 0A], [0A, 0A, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) ---------------------------------------- (8) Obligation: Q DP problem: P is empty. The TRS R consists of the following rules: a(x1) -> x1 a(b(b(a(x1)))) -> a(a(b(a(b(b(x1)))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (9) PisEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R) chain. ---------------------------------------- (10) YES