YES

Problem:
 a(x1) -> x1
 a(b(x1)) -> b(a(c(x1)))
 b(x1) -> x1
 c(c(x1)) -> b(a(x1))

Proof:
 String Reversal Processor:
  a(x1) -> x1
  b(a(x1)) -> c(a(b(x1)))
  b(x1) -> x1
  c(c(x1)) -> a(b(x1))
  DP Processor:
   DPs:
    b#(a(x1)) -> b#(x1)
    b#(a(x1)) -> a#(b(x1))
    b#(a(x1)) -> c#(a(b(x1)))
    c#(c(x1)) -> b#(x1)
    c#(c(x1)) -> a#(b(x1))
   TRS:
    a(x1) -> x1
    b(a(x1)) -> c(a(b(x1)))
    b(x1) -> x1
    c(c(x1)) -> a(b(x1))
   TDG Processor:
    DPs:
     b#(a(x1)) -> b#(x1)
     b#(a(x1)) -> a#(b(x1))
     b#(a(x1)) -> c#(a(b(x1)))
     c#(c(x1)) -> b#(x1)
     c#(c(x1)) -> a#(b(x1))
    TRS:
     a(x1) -> x1
     b(a(x1)) -> c(a(b(x1)))
     b(x1) -> x1
     c(c(x1)) -> a(b(x1))
    graph:
     c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1)))
     c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1))
     c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1)
     b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> a#(b(x1))
     b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> b#(x1)
     b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1)))
     b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1))
     b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1)
    SCC Processor:
     #sccs: 1
     #rules: 3
     #arcs: 8/25
     DPs:
      c#(c(x1)) -> b#(x1)
      b#(a(x1)) -> b#(x1)
      b#(a(x1)) -> c#(a(b(x1)))
     TRS:
      a(x1) -> x1
      b(a(x1)) -> c(a(b(x1)))
      b(x1) -> x1
      c(c(x1)) -> a(b(x1))
     Arctic Interpretation Processor:
      dimension: 2
      usable rules:
       a(x1) -> x1
       b(a(x1)) -> c(a(b(x1)))
       b(x1) -> x1
       c(c(x1)) -> a(b(x1))
      interpretation:
       [b#](x0) = [2 1]x0,
       
                 [0  -&]     [2]
       [b](x0) = [1  0 ]x0 + [2],
       
       [c#](x0) = [-& 1 ]x0 + [0],
       
                 [1  0 ]     [3]
       [a](x0) = [-& 0 ]x0 + [3],
       
                 [0 0]     [3]
       [c](x0) = [1 0]x0 + [0]
      orientation:
       c#(c(x1)) = [2 1]x1 + [1] >= [2 1]x1 = b#(x1)
       
       b#(a(x1)) = [3 2]x1 + [5] >= [2 1]x1 = b#(x1)
       
       b#(a(x1)) = [3 2]x1 + [5] >= [2 1]x1 + [4] = c#(a(b(x1)))
       
               [1  0 ]     [3]           
       a(x1) = [-& 0 ]x1 + [3] >= x1 = x1
       
                  [1 0]     [3]    [1 0]     [3]              
       b(a(x1)) = [2 1]x1 + [4] >= [2 1]x1 + [4] = c(a(b(x1)))
       
               [0  -&]     [2]           
       b(x1) = [1  0 ]x1 + [2] >= x1 = x1
       
                  [1 0]     [3]    [1 0]     [3]           
       c(c(x1)) = [1 1]x1 + [4] >= [1 0]x1 + [3] = a(b(x1))
      problem:
       DPs:
        c#(c(x1)) -> b#(x1)
       TRS:
        a(x1) -> x1
        b(a(x1)) -> c(a(b(x1)))
        b(x1) -> x1
        c(c(x1)) -> a(b(x1))
      Restore Modifier:
       DPs:
        c#(c(x1)) -> b#(x1)
       TRS:
        a(x1) -> x1
        b(a(x1)) -> c(a(b(x1)))
        b(x1) -> x1
        c(c(x1)) -> a(b(x1))
       EDG Processor:
        DPs:
         c#(c(x1)) -> b#(x1)
        TRS:
         a(x1) -> x1
         b(a(x1)) -> c(a(b(x1)))
         b(x1) -> x1
         c(c(x1)) -> a(b(x1))
        graph:
         
        SCC Processor:
         #sccs: 0
         #rules: 0
         #arcs: 0/1