YES Problem: a(x1) -> x1 a(b(c(x1))) -> c(c(a(b(b(x1))))) b(x1) -> a(x1) Proof: String Reversal Processor: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) DP Processor: DPs: c#(b(a(x1))) -> c#(x1) c#(b(a(x1))) -> c#(c(x1)) c#(b(a(x1))) -> a#(c(c(x1))) c#(b(a(x1))) -> b#(a(c(c(x1)))) c#(b(a(x1))) -> b#(b(a(c(c(x1))))) b#(x1) -> a#(x1) TRS: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) TDG Processor: DPs: c#(b(a(x1))) -> c#(x1) c#(b(a(x1))) -> c#(c(x1)) c#(b(a(x1))) -> a#(c(c(x1))) c#(b(a(x1))) -> b#(a(c(c(x1)))) c#(b(a(x1))) -> b#(b(a(c(c(x1))))) b#(x1) -> a#(x1) TRS: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) graph: c#(b(a(x1))) -> b#(b(a(c(c(x1))))) -> b#(x1) -> a#(x1) c#(b(a(x1))) -> b#(a(c(c(x1)))) -> b#(x1) -> a#(x1) c#(b(a(x1))) -> c#(c(x1)) -> c#(b(a(x1))) -> b#(b(a(c(c(x1))))) c#(b(a(x1))) -> c#(c(x1)) -> c#(b(a(x1))) -> b#(a(c(c(x1)))) c#(b(a(x1))) -> c#(c(x1)) -> c#(b(a(x1))) -> a#(c(c(x1))) c#(b(a(x1))) -> c#(c(x1)) -> c#(b(a(x1))) -> c#(c(x1)) c#(b(a(x1))) -> c#(c(x1)) -> c#(b(a(x1))) -> c#(x1) c#(b(a(x1))) -> c#(x1) -> c#(b(a(x1))) -> b#(b(a(c(c(x1))))) c#(b(a(x1))) -> c#(x1) -> c#(b(a(x1))) -> b#(a(c(c(x1)))) c#(b(a(x1))) -> c#(x1) -> c#(b(a(x1))) -> a#(c(c(x1))) c#(b(a(x1))) -> c#(x1) -> c#(b(a(x1))) -> c#(c(x1)) c#(b(a(x1))) -> c#(x1) -> c#(b(a(x1))) -> c#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 12/36 DPs: c#(b(a(x1))) -> c#(c(x1)) c#(b(a(x1))) -> c#(x1) TRS: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) interpretation: [c#](x0) = [0 0]x0 + [0], [0 0] [-&] [c](x0) = [0 0]x0 + [0 ], [0 0] [a](x0) = [0 0]x0, [0 0] [-&] [b](x0) = [1 0]x0 + [2 ] orientation: c#(b(a(x1))) = [1 1]x1 + [2] >= [0 0]x1 + [0] = c#(c(x1)) c#(b(a(x1))) = [1 1]x1 + [2] >= [0 0]x1 + [0] = c#(x1) [0 0] a(x1) = [0 0]x1 >= x1 = x1 [1 1] [2] [1 1] [2] c(b(a(x1))) = [1 1]x1 + [2] >= [1 1]x1 + [2] = b(b(a(c(c(x1))))) [0 0] [-&] [0 0] b(x1) = [1 0]x1 + [2 ] >= [0 0]x1 = a(x1) problem: DPs: TRS: a(x1) -> x1 c(b(a(x1))) -> b(b(a(c(c(x1))))) b(x1) -> a(x1) Qed