YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (2) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(X) -> g The set Q consists of the following terms: f(x0) ---------------------------------------- (1) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 0. This implies Q-termination of R. The following rules were used to construct the certificate: f(X) -> g The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 1, 2 Node 1 is start node and node 2 is final node. Those nodes are connected through the following edges: * 1 to 2 labelled g(0)* 2 to 2 labelled #_1(0) ---------------------------------------- (2) YES