YES Problem 1: (VAR v_NonEmpty:S X:S X1:S X2:S X3:S) (RULES a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ) (STRATEGY INNERMOST) Problem 1: Dependency Pairs Processor: -> Pairs: A__F(a,b,X:S) -> A__F(X:S,X:S,mark(X:S)) A__F(a,b,X:S) -> MARK(X:S) MARK(c) -> A__C MARK(f(X1:S,X2:S,X3:S)) -> A__F(X1:S,X2:S,mark(X3:S)) MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) Problem 1: SCC Processor: -> Pairs: A__F(a,b,X:S) -> A__F(X:S,X:S,mark(X:S)) A__F(a,b,X:S) -> MARK(X:S) MARK(c) -> A__C MARK(f(X1:S,X2:S,X3:S)) -> A__F(X1:S,X2:S,mark(X3:S)) MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A__F(a,b,X:S) -> MARK(X:S) MARK(f(X1:S,X2:S,X3:S)) -> A__F(X1:S,X2:S,mark(X3:S)) MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) ->->-> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) Problem 1: Reduction Pairs Processor: -> Pairs: A__F(a,b,X:S) -> MARK(X:S) MARK(f(X1:S,X2:S,X3:S)) -> A__F(X1:S,X2:S,mark(X3:S)) MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) -> Usable rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [a__c] = 2 [a__f](X1,X2,X3) = 2.X3 + 2 [mark](X) = X [a] = 2 [b] = 2 [c] = 2 [f](X1,X2,X3) = 2.X3 + 2 [fSNonEmpty] = 0 [A__C] = 0 [A__F](X1,X2,X3) = 2.X3 + 2 [MARK](X) = X + 1 Problem 1: SCC Processor: -> Pairs: MARK(f(X1:S,X2:S,X3:S)) -> A__F(X1:S,X2:S,mark(X3:S)) MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) ->->-> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) Problem 1: Subterm Processor: -> Pairs: MARK(f(X1:S,X2:S,X3:S)) -> MARK(X3:S) -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ->Projection: pi(MARK) = 1 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: a__c -> a a__c -> b a__c -> c a__f(a,b,X:S) -> a__f(X:S,X:S,mark(X:S)) a__f(X1:S,X2:S,X3:S) -> f(X1:S,X2:S,X3:S) mark(a) -> a mark(b) -> b mark(c) -> a__c mark(f(X1:S,X2:S,X3:S)) -> a__f(X1:S,X2:S,mark(X3:S)) ->Strongly Connected Components: There is no strongly connected component The problem is finite.