YES proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 64 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (10) IntTRS (11) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (12) IntTRS (13) RankingReductionPairProof [EQUIVALENT, 3 ms] (14) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(c, x, y) -> f2(c, x_1, y) :|: TRUE f2(x1, x2, x3) -> f3(x1, x2, x4) :|: TRUE f3(x5, x6, x7) -> f4(0, x6, x7) :|: TRUE f6(x8, x9, x10) -> f7(x8, x9, arith) :|: TRUE && arith = x10 - 1 f7(x38, x39, x40) -> f8(x41, x39, x40) :|: TRUE && x41 = x38 + 1 f5(x14, x15, x16) -> f6(x14, x15, x16) :|: x16 > 0 f8(x17, x18, x19) -> f5(x17, x18, x19) :|: TRUE f5(x20, x21, x22) -> f9(x20, x21, x22) :|: x22 <= 0 f9(x42, x43, x44) -> f10(x42, x45, x44) :|: TRUE && x45 = x43 - 1 f10(x46, x47, x48) -> f11(x49, x47, x48) :|: TRUE && x49 = x46 + 1 f4(x29, x30, x31) -> f5(x29, x30, x31) :|: x30 > 0 f11(x32, x33, x34) -> f4(x32, x33, x34) :|: TRUE f4(x35, x36, x37) -> f12(x35, x36, x37) :|: x36 <= 0 Start term: f1(c, x, y) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x29, x30, x31) -> f5(x29, x30, x31) :|: x30 > 0 f11(x32, x33, x34) -> f4(x32, x33, x34) :|: TRUE f10(x46, x47, x48) -> f11(x49, x47, x48) :|: TRUE && x49 = x46 + 1 f9(x42, x43, x44) -> f10(x42, x45, x44) :|: TRUE && x45 = x43 - 1 f5(x20, x21, x22) -> f9(x20, x21, x22) :|: x22 <= 0 f8(x17, x18, x19) -> f5(x17, x18, x19) :|: TRUE f7(x38, x39, x40) -> f8(x41, x39, x40) :|: TRUE && x41 = x38 + 1 f6(x8, x9, x10) -> f7(x8, x9, arith) :|: TRUE && arith = x10 - 1 f5(x14, x15, x16) -> f6(x14, x15, x16) :|: x16 > 0 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f5(x14:0, x15:0, x16:0) -> f5(x14:0 + 1, x15:0, x16:0 - 1) :|: x16:0 > 0 f5(x20:0, x21:0, x22:0) -> f5(x20:0 + 1, x21:0 - 1, x22:0) :|: x22:0 < 1 && x21:0 > 1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f5(x1, x2, x3) -> f5(x2, x3) ---------------------------------------- (8) Obligation: Rules: f5(x15:0, x16:0) -> f5(x15:0, x16:0 - 1) :|: x16:0 > 0 f5(x21:0, x22:0) -> f5(x21:0 - 1, x22:0) :|: x22:0 < 1 && x21:0 > 1 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f5(x, x1)] = -1 + x The following rules are decreasing: f5(x21:0, x22:0) -> f5(x21:0 - 1, x22:0) :|: x22:0 < 1 && x21:0 > 1 The following rules are bounded: f5(x21:0, x22:0) -> f5(x21:0 - 1, x22:0) :|: x22:0 < 1 && x21:0 > 1 ---------------------------------------- (10) Obligation: Rules: f5(x15:0, x16:0) -> f5(x15:0, x16:0 - 1) :|: x16:0 > 0 ---------------------------------------- (11) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f5(x1, x2) -> f5(x2) ---------------------------------------- (12) Obligation: Rules: f5(x16:0) -> f5(x16:0 - 1) :|: x16:0 > 0 ---------------------------------------- (13) RankingReductionPairProof (EQUIVALENT) Interpretation: [ f5 ] = f5_1 The following rules are decreasing: f5(x16:0) -> f5(x16:0 - 1) :|: x16:0 > 0 The following rules are bounded: f5(x16:0) -> f5(x16:0 - 1) :|: x16:0 > 0 ---------------------------------------- (14) YES