NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.c
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination of the given C Problem could be disproven:

(0) C Problem
(1) CToIRSProof [EQUIVALENT, 0 ms]
(2) IntTRS
(3) IRS2T2 [EQUIVALENT, 0 ms]
(4) T2IntSys
(5) T2 [COMPLETE, 2414 ms]
(6) NO


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(0)
Obligation:
c file /export/starexec/sandbox2/benchmark/theBenchmark.c
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(1) CToIRSProof (EQUIVALENT)
Parsed C Integer Program as IRS.
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(2)
Obligation:
Rules:
f1(i, range) -> f2(x_1, range) :|: TRUE
f2(x, x1) -> f3(x, 20) :|: TRUE
f5(x2, x3) -> f8(arith, x3) :|: TRUE && arith = x2 * (0 - 1)
f6(x32, x33) -> f9(x32, x34) :|: TRUE && x34 = x33 + 1
f9(x35, x36) -> f10(x37, x36) :|: TRUE && x37 = x35 - 1
f11(x38, x39) -> f14(x38, x40) :|: TRUE && x40 = 0 - 1
f10(x10, x11) -> f11(x10, x11) :|: x10 = 0
f10(x12, x13) -> f12(x12, x13) :|: x12 < 0
f10(x41, x42) -> f12(x41, x42) :|: x41 > 0
f14(x14, x15) -> f13(x14, x15) :|: TRUE
f12(x16, x17) -> f13(x16, x17) :|: TRUE
f4(x18, x19) -> f5(x18, x19) :|: x19 - x18 < 5
f4(x43, x44) -> f5(x43, x44) :|: x44 + x43 < 5
f4(x20, x21) -> f6(x20, x21) :|: x21 - x20 >= 5 && x21 + x20 >= 5
f8(x22, x23) -> f7(x22, x23) :|: TRUE
f13(x24, x25) -> f7(x24, x25) :|: TRUE
f3(x26, x27) -> f4(x26, x27) :|: 0 - x27 <= x26 && x26 <= x27
f7(x28, x29) -> f3(x28, x29) :|: TRUE
f3(x30, x31) -> f15(x30, x31) :|: 0 - x31 > x30
f3(x45, x46) -> f15(x45, x46) :|: x45 > x46
Start term: f1(i, range)

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(3) IRS2T2 (EQUIVALENT)
Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs:

   (f1_2,1)
   (f2_2,2)
   (f3_2,3)
   (f5_2,4)
   (f8_2,5)
   (f6_2,6)
   (f9_2,7)
   (f10_2,8)
   (f11_2,9)
   (f14_2,10)
   (f12_2,11)
   (f13_2,12)
   (f4_2,13)
   (f7_2,14)
   (f15_2,15)

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(4)
Obligation:
START: 1;

FROM: 1;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX2;
x1 := oldX1;
TO: 2;

FROM: 2;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := 20;
TO: 3;

FROM: 4;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0 && oldX2 = oldX0 * (0 - 1));
x0 := oldX2;
x1 := oldX1;
TO: 5;

FROM: 6;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(-(oldX1 + 1));
assume(0 = 0 && oldX2 = oldX1 + 1);
x0 := oldX0;
x1 := -(-(oldX1 + 1));
TO: 7;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(1 - oldX0);
assume(0 = 0 && oldX2 = oldX0 - 1);
x0 := -(1 - oldX0);
x1 := oldX1;
TO: 8;

FROM: 9;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(1);
assume(0 = 0 && oldX2 = 0 - 1);
x0 := oldX0;
x1 := -(1);
TO: 10;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 9;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 < 0);
x0 := oldX0;
x1 := oldX1;
TO: 11;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 > 0);
x0 := oldX0;
x1 := oldX1;
TO: 11;

FROM: 10;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 12;

FROM: 11;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 12;

FROM: 13;
oldX0 := x0;
oldX1 := x1;
assume(oldX1 - oldX0 < 5);
x0 := oldX0;
x1 := oldX1;
TO: 4;

FROM: 13;
oldX0 := x0;
oldX1 := x1;
assume(oldX1 + oldX0 < 5);
x0 := oldX0;
x1 := oldX1;
TO: 4;

FROM: 13;
oldX0 := x0;
oldX1 := x1;
assume(oldX1 - oldX0 >= 5 && oldX1 + oldX0 >= 5);
x0 := oldX0;
x1 := oldX1;
TO: 6;

FROM: 5;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 14;

FROM: 12;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 14;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(0 - oldX1 <= oldX0 && oldX0 <= oldX1);
x0 := oldX0;
x1 := oldX1;
TO: 13;

FROM: 14;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 3;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(0 - oldX1 > oldX0);
x0 := oldX0;
x1 := oldX1;
TO: 15;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 > oldX1);
x0 := oldX0;
x1 := oldX1;
TO: 15;


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(5) T2 (COMPLETE)
Found this recurrent set for cutpoint 12: -16 <= oldX2 and oldX2 <= -1 and x0 <= -1 and 21 <= x1 and x0-oldX2 <= 0 and oldX2+x0 <= -2 and oldX2-x1 <= -22 and 5 <= oldX2+x1 and x0-x1 <= -22 and x0+x1 <= 20 and 5 <= x0+x1 and -x1-x0 <= 0 and -x1+x0 <= 0

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(6)
NO