NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.c
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination of the given C Problem could be disproven:

(0) C Problem
(1) CToIRSProof [EQUIVALENT, 0 ms]
(2) IntTRS
(3) IRS2T2 [EQUIVALENT, 0 ms]
(4) T2IntSys
(5) T2 [COMPLETE, 1474 ms]
(6) NO


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(0)
Obligation:
c file /export/starexec/sandbox2/benchmark/theBenchmark.c
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(1) CToIRSProof (EQUIVALENT)
Parsed C Integer Program as IRS.
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(2)
Obligation:
Rules:
f1(a, b) -> f2(1, b) :|: TRUE
f2(x, x1) -> f3(x, 2) :|: TRUE
f4(x2, x3) -> f5(arith, x3) :|: TRUE && arith = x2 - x3
f5(x14, x15) -> f6(x14, x16) :|: TRUE && x16 = x14 + x15
f6(x17, x18) -> f7(x19, x18) :|: TRUE && x19 = x18 - x17
f3(x8, x9) -> f4(x8, x9) :|: x8 + x9 < 5
f7(x10, x11) -> f3(x10, x11) :|: TRUE
f3(x12, x13) -> f8(x12, x13) :|: x12 + x13 >= 5
Start term: f1(a, b)

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(3) IRS2T2 (EQUIVALENT)
Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs:

   (f1_2,1)
   (f2_2,2)
   (f3_2,3)
   (f4_2,4)
   (f5_2,5)
   (f6_2,6)
   (f7_2,7)
   (f8_2,8)

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(4)
Obligation:
START: 1;

FROM: 1;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := 1;
x1 := oldX1;
TO: 2;

FROM: 2;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := 2;
TO: 3;

FROM: 4;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(oldX1 - oldX0);
assume(0 = 0 && oldX2 = oldX0 - oldX1);
x0 := -(oldX1 - oldX0);
x1 := oldX1;
TO: 5;

FROM: 5;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(-(oldX0 + oldX1));
assume(0 = 0 && oldX2 = oldX0 + oldX1);
x0 := oldX0;
x1 := -(-(oldX0 + oldX1));
TO: 6;

FROM: 6;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(oldX0 - oldX1);
assume(0 = 0 && oldX2 = oldX1 - oldX0);
x0 := -(oldX0 - oldX1);
x1 := oldX1;
TO: 7;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 < 5);
x0 := oldX0;
x1 := oldX1;
TO: 4;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 3;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 >= 5);
x0 := oldX0;
x1 := oldX1;
TO: 8;


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(5) T2 (COMPLETE)
Found this recurrent set for cutpoint 6: oldX0 == 1 and x0 == 1 and x1 == 2 or oldX0 == 2 and x0 == 2 and x1 == 1

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(6)
NO