YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 60 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 10 ms] (10) IntTRS (11) RankingReductionPairProof [EQUIVALENT, 4 ms] (12) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(c, i, j) -> f2(c, x_1, j) :|: TRUE f2(x, x1, x2) -> f3(x, x1, x3) :|: TRUE f3(x4, x5, x6) -> f4(0, x5, x6) :|: TRUE f5(x7, x8, x9) -> f6(x7, x8, 0) :|: TRUE f7(x10, x11, x12) -> f8(x10, x11, arith) :|: TRUE && arith = x12 + 1 f8(x37, x38, x39) -> f9(x40, x38, x39) :|: TRUE && x40 = x37 + 1 f6(x16, x17, x18) -> f7(x16, x17, x18) :|: x18 <= x17 - 1 f9(x19, x20, x21) -> f6(x19, x20, x21) :|: TRUE f6(x22, x23, x24) -> f10(x22, x23, x24) :|: x24 > x23 - 1 f10(x41, x42, x43) -> f11(x41, x44, x43) :|: TRUE && x44 = x42 - 1 f4(x28, x29, x30) -> f5(x28, x29, x30) :|: x29 >= 0 f11(x31, x32, x33) -> f4(x31, x32, x33) :|: TRUE f4(x34, x35, x36) -> f12(x34, x35, x36) :|: x35 < 0 Start term: f1(c, i, j) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x28, x29, x30) -> f5(x28, x29, x30) :|: x29 >= 0 f11(x31, x32, x33) -> f4(x31, x32, x33) :|: TRUE f10(x41, x42, x43) -> f11(x41, x44, x43) :|: TRUE && x44 = x42 - 1 f6(x22, x23, x24) -> f10(x22, x23, x24) :|: x24 > x23 - 1 f5(x7, x8, x9) -> f6(x7, x8, 0) :|: TRUE f9(x19, x20, x21) -> f6(x19, x20, x21) :|: TRUE f8(x37, x38, x39) -> f9(x40, x38, x39) :|: TRUE && x40 = x37 + 1 f7(x10, x11, x12) -> f8(x10, x11, arith) :|: TRUE && arith = x12 + 1 f6(x16, x17, x18) -> f7(x16, x17, x18) :|: x18 <= x17 - 1 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f6(x16:0, x17:0, x18:0) -> f6(x16:0 + 1, x17:0, x18:0 + 1) :|: x18:0 <= x17:0 - 1 f6(x22:0, x23:0, x24:0) -> f6(x22:0, x23:0 - 1, 0) :|: x24:0 > x23:0 - 1 && x23:0 > 0 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f6(x1, x2, x3) -> f6(x2, x3) ---------------------------------------- (8) Obligation: Rules: f6(x17:0, x18:0) -> f6(x17:0, x18:0 + 1) :|: x18:0 <= x17:0 - 1 f6(x23:0, x24:0) -> f6(x23:0 - 1, 0) :|: x24:0 > x23:0 - 1 && x23:0 > 0 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f6(x, x1)] = -1 + x The following rules are decreasing: f6(x23:0, x24:0) -> f6(x23:0 - 1, 0) :|: x24:0 > x23:0 - 1 && x23:0 > 0 The following rules are bounded: f6(x23:0, x24:0) -> f6(x23:0 - 1, 0) :|: x24:0 > x23:0 - 1 && x23:0 > 0 ---------------------------------------- (10) Obligation: Rules: f6(x17:0, x18:0) -> f6(x17:0, x18:0 + 1) :|: x18:0 <= x17:0 - 1 ---------------------------------------- (11) RankingReductionPairProof (EQUIVALENT) Interpretation: [ f6 ] = -1*f6_2 + f6_1 The following rules are decreasing: f6(x17:0, x18:0) -> f6(x17:0, x18:0 + 1) :|: x18:0 <= x17:0 - 1 The following rules are bounded: f6(x17:0, x18:0) -> f6(x17:0, x18:0 + 1) :|: x18:0 <= x17:0 - 1 ---------------------------------------- (12) YES