NO proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be disproven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) IRS2T2 [EQUIVALENT, 0 ms] (4) T2IntSys (5) T2 [COMPLETE, 1584 ms] (6) NO ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i) -> f2(0) :|: TRUE f4(x) -> f7(arith) :|: TRUE && arith = x + 1 f5(x9) -> f8(x10) :|: TRUE && x10 = x9 - 1 f3(x2) -> f4(x2) :|: x2 < 50 f3(x3) -> f5(x3) :|: x3 >= 50 f7(x4) -> f6(x4) :|: TRUE f8(x5) -> f6(x5) :|: TRUE f2(x6) -> f3(x6) :|: x6 < 100 f6(x7) -> f2(x7) :|: TRUE f2(x8) -> f9(x8) :|: x8 >= 100 Start term: f1(i) ---------------------------------------- (3) IRS2T2 (EQUIVALENT) Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs: (f1_1,1) (f2_1,2) (f4_1,3) (f7_1,4) (f5_1,5) (f8_1,6) (f3_1,7) (f6_1,8) (f9_1,9) ---------------------------------------- (4) Obligation: START: 1; FROM: 1; oldX0 := x0; assume(0 = 0); x0 := 0; TO: 2; FROM: 3; oldX0 := x0; oldX1 := -(-(oldX0 + 1)); assume(0 = 0 && oldX1 = oldX0 + 1); x0 := -(-(oldX0 + 1)); TO: 4; FROM: 5; oldX0 := x0; oldX1 := -(1 - oldX0); assume(0 = 0 && oldX1 = oldX0 - 1); x0 := -(1 - oldX0); TO: 6; FROM: 7; oldX0 := x0; assume(oldX0 < 50); x0 := oldX0; TO: 3; FROM: 7; oldX0 := x0; assume(oldX0 >= 50); x0 := oldX0; TO: 5; FROM: 4; oldX0 := x0; assume(0 = 0); x0 := oldX0; TO: 8; FROM: 6; oldX0 := x0; assume(0 = 0); x0 := oldX0; TO: 8; FROM: 2; oldX0 := x0; assume(oldX0 < 100); x0 := oldX0; TO: 7; FROM: 8; oldX0 := x0; assume(0 = 0); x0 := oldX0; TO: 2; FROM: 2; oldX0 := x0; assume(oldX0 >= 100); x0 := oldX0; TO: 9; ---------------------------------------- (5) T2 (COMPLETE) Found this recurrent set for cutpoint 8: 5 <= x0 and x0 <= 5 and x0+-99 <= 0 ---------------------------------------- (6) NO