NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.c
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination of the given C Problem could be disproven:

(0) C Problem
(1) CToLLVMProof [EQUIVALENT, 146 ms]
(2) LLVM problem
(3) LLVMToTerminationGraphProof [EQUIVALENT, 303 ms]
(4) LLVM Symbolic Execution Graph
(5) LLVMNonterminationProof [COMPLETE, 132 ms]
(6) NO


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(0)
Obligation:
c file /export/starexec/sandbox2/benchmark/theBenchmark.c
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(1) CToLLVMProof (EQUIVALENT)
Compiled c-file /export/starexec/sandbox2/benchmark/theBenchmark.c to LLVM.
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(2)
Obligation:
LLVM Problem

Aliases:

Data layout:

"e-p:64:64:64-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:64:64-f32:32:32-f64:64:64-v64:64:64-v128:128:128-a0:0:64-s0:64:64-f80:128:128-n8:16:32:64-S128"

Machine:

"x86_64-pc-linux-gnu"

Type definitions:

Global variables:

Function declarations and definitions:

*BasicFunctionTypename: "main" linkageType: EXTERNALLY_VISIBLE returnParam: i32 parameters: () variableLength: false visibilityType: DEFAULT callingConvention: ccc
	0:
		%1 = alloca i32, align 4
		%i = alloca i32, align 4
		%j = alloca i32, align 4
		store 0, %1
		store 0, %i
		br %2
	2:
		%3 = load %i
		%4 = icmp slt %3 100
		br %4, %5, %15
	5:
		store 0, %j
		br %6
	6:
		%7 = load %j
		%8 = icmp slt %7 1
		br %8, %9, %12
	9:
		%10 = load %j
		%11 = add %10 1
		store %11, %j
		br %6
	12:
		%13 = load %i
		%14 = add %13 0
		store %14, %i
		br %2
	15:
		ret 0


Analyze Termination of all function calls matching the pattern:
main()
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(3) LLVMToTerminationGraphProof (EQUIVALENT)
Constructed symbolic execution graph for LLVM program and proved memory safety.
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(4)
Obligation:
SE Graph
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(5) LLVMNonterminationProof (COMPLETE)
Proved nontermination with the following witness:

State #71 with references set to {}.
Nondeterministic instruction %1 = alloca i32, align 4 in node #71 yields value 11.
Nondeterministic instruction %i = alloca i32, align 4 in node #72 yields value 5.
Nondeterministic instruction %j = alloca i32, align 4 in node #73 yields value 1.

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(6)
NO