/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES

Problem:
 a(b(a(a(x1)))) -> a(a(b(a(x1))))
 b(b(a(a(x1)))) -> a(a(a(b(x1))))
 b(a(a(b(x1)))) -> b(b(b(a(x1))))

Proof:
 Matrix Interpretation Processor: dim=3
  
  interpretation:
             [1 0 1]  
   [b](x0) = [1 0 1]x0
             [0 1 0]  ,
   
             [1 0 1]     [0]
   [a](x0) = [1 0 1]x0 + [0]
             [0 1 0]     [1]
  orientation:
                    [3 2 3]     [3]    [3 2 3]     [3]                 
   a(b(a(a(x1)))) = [3 2 3]x1 + [3] >= [3 2 3]x1 + [3] = a(a(b(a(x1))))
                    [2 1 2]     [3]    [2 1 2]     [2]                 
   
                    [3 2 3]     [3]    [3 2 3]     [2]                 
   b(b(a(a(x1)))) = [3 2 3]x1 + [3] >= [3 2 3]x1 + [2] = a(a(a(b(x1))))
                    [2 1 2]     [2]    [2 1 2]     [2]                 
   
                    [3 2 3]     [2]    [3 2 3]     [2]                 
   b(a(a(b(x1)))) = [3 2 3]x1 + [2] >= [3 2 3]x1 + [2] = b(b(b(a(x1))))
                    [2 1 2]     [1]    [2 1 2]     [1]                 
  problem:
   a(b(a(a(x1)))) -> a(a(b(a(x1))))
   b(a(a(b(x1)))) -> b(b(b(a(x1))))
  KBO Processor:
   weight function:
    w0 = 1
    w(a) = 1
    w(b) = 0
   precedence:
    b > a
   problem:
    
   Qed