/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES

Problem:
 b(b(b(b(x1)))) -> b(b(a(a(x1))))
 b(b(a(a(x1)))) -> a(b(a(b(x1))))
 a(b(a(a(x1)))) -> a(b(a(b(x1))))

Proof:
 String Reversal Processor:
  b(b(b(b(x1)))) -> a(a(b(b(x1))))
  a(a(b(b(x1)))) -> b(a(b(a(x1))))
  a(a(b(a(x1)))) -> b(a(b(a(x1))))
  Matrix Interpretation Processor: dim=4
   
   interpretation:
              [1 0 0 0]  
              [0 0 1 0]  
    [a](x0) = [0 1 0 0]x0
              [0 0 0 0]  ,
    
              [1 0 0 1]     [0]
              [0 0 0 0]     [0]
    [b](x0) = [0 0 0 0]x0 + [1]
              [0 0 1 0]     [0]
   orientation:
                     [1 0 1 1]     [2]    [1 0 1 1]     [0]                 
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
    b(b(b(b(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(b(b(x1))))
                     [0 0 0 0]     [1]    [0 0 0 0]     [0]                 
    
                     [1 0 1 1]     [0]    [1 0 0 0]     [0]                 
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
    a(a(b(b(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(a(b(a(x1))))
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
    
                     [1 0 0 0]     [0]    [1 0 0 0]     [0]                 
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
    a(a(b(a(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(a(b(a(x1))))
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
   problem:
    a(a(b(b(x1)))) -> b(a(b(a(x1))))
    a(a(b(a(x1)))) -> b(a(b(a(x1))))
   KBO Processor:
    weight function:
     w0 = 1
     w(a) = w(b) = 1
    precedence:
     a > b
    problem:
     
    Qed