/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES

Problem:
 b(a(b(b(x1)))) -> b(b(b(b(x1))))
 b(b(a(a(x1)))) -> a(a(b(b(x1))))
 b(a(b(b(x1)))) -> b(a(a(a(x1))))

Proof:
 Matrix Interpretation Processor: dim=3
  
  interpretation:
             [1 0 0]  
   [a](x0) = [0 0 1]x0
             [0 1 0]  ,
   
             [1 0 1]     [0]
   [b](x0) = [0 1 2]x0 + [1]
             [0 0 0]     [0]
  orientation:
                    [1 1 3]     [2]    [1 0 1]     [0]                 
   b(a(b(b(x1)))) = [0 2 4]x1 + [5] >= [0 1 2]x1 + [4] = b(b(b(b(x1))))
                    [0 0 0]     [0]    [0 0 0]     [0]                 
   
                    [1 0 1]     [0]    [1 0 1]     [0]                 
   b(b(a(a(x1)))) = [0 1 2]x1 + [2] >= [0 1 2]x1 + [2] = a(a(b(b(x1))))
                    [0 0 0]     [0]    [0 0 0]     [0]                 
   
                    [1 1 3]     [2]    [1 1 0]     [0]                 
   b(a(b(b(x1)))) = [0 2 4]x1 + [5] >= [0 2 1]x1 + [1] = b(a(a(a(x1))))
                    [0 0 0]     [0]    [0 0 0]     [0]                 
  problem:
   b(b(a(a(x1)))) -> a(a(b(b(x1))))
  KBO Processor:
   weight function:
    w0 = 1
    w(a) = 1
    w(b) = 0
   precedence:
    b > a
   problem:
    
   Qed