/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: b(a(a(b(x1)))) -> b(a(a(a(x1)))) a(b(b(a(x1)))) -> a(a(b(b(x1)))) b(a(a(a(x1)))) -> b(b(b(a(x1)))) Proof: Matrix Interpretation Processor: dim=4 interpretation: [1 0 1 0] [0] [0 0 1 1] [0] [a](x0) = [0 0 0 0]x0 + [0] [0 1 1 0] [1], [1 0 0 0] [0] [0 0 0 0] [0] [b](x0) = [0 1 1 1]x0 + [0] [0 0 0 0] [1] orientation: [1 1 1 1] [0] [1 0 1 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] b(a(a(b(x1)))) = [0 2 2 2]x1 + [3] >= [0 1 2 1]x1 + [3] = b(a(a(a(x1)))) [0 0 0 0] [1] [0 0 0 0] [1] [1 1 3 1] [2] [1 1 1 1] [1] [0 1 2 1] [3] [0 1 1 1] [2] a(b(b(a(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = a(a(b(b(x1)))) [0 1 2 1] [3] [0 1 1 1] [3] [1 0 1 0] [0] [1 0 1 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] b(a(a(a(x1)))) = [0 1 2 1]x1 + [3] >= [0 1 2 1]x1 + [3] = b(b(b(a(x1)))) [0 0 0 0] [1] [0 0 0 0] [1] problem: b(a(a(b(x1)))) -> b(a(a(a(x1)))) b(a(a(a(x1)))) -> b(b(b(a(x1)))) Bounds Processor: bound: 1 enrichment: match automaton: final states: {6,1} transitions: b1(11) -> 12* b1(12) -> 13* b1(10) -> 11* a1(9) -> 10* f20() -> 2* a0(3) -> 4* a0(4) -> 5* a0(2) -> 3* b0(5) -> 1* b0(7) -> 8* b0(8) -> 6* b0(3) -> 7* 2 -> 9* 13 -> 1* 1 -> 11,7 problem: Qed