/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo { b->0, a->1, c->2 }, it remains to prove termination of the 5-rule system { 0 1 1 -> 1 0 2 , 2 1 -> 1 2 , 0 2 1 -> 1 0 2 , 2 0 -> 0 1 , 1 2 0 -> 2 0 1 } The length-preserving system was inverted. After renaming modulo { 1->0, 0->1, 2->2 }, it remains to prove termination of the 5-rule system { 0 1 2 -> 1 0 0 , 0 2 -> 2 0 , 0 1 2 -> 1 2 0 , 1 0 -> 2 1 , 2 1 0 -> 0 2 1 } The system was reversed. After renaming modulo { 2->0, 1->1, 0->2 }, it remains to prove termination of the 5-rule system { 0 1 2 -> 2 2 1 , 0 2 -> 2 0 , 0 1 2 -> 2 0 1 , 2 1 -> 1 0 , 2 1 0 -> 1 0 2 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (1,false)->1, (2,false)->2, (2,true)->3, (0,false)->4 }, it remains to prove termination of the 14-rule system { 0 1 2 -> 3 2 1 , 0 1 2 -> 3 1 , 0 2 -> 3 4 , 0 2 -> 0 , 0 1 2 -> 3 4 1 , 0 1 2 -> 0 1 , 3 1 -> 0 , 3 1 4 -> 0 2 , 3 1 4 -> 3 , 4 1 2 ->= 2 2 1 , 4 2 ->= 2 4 , 4 1 2 ->= 2 4 1 , 2 1 ->= 1 4 , 2 1 4 ->= 1 4 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4 }, it remains to prove termination of the 8-rule system { 0 1 2 -> 3 2 1 , 0 2 -> 3 4 , 0 1 2 -> 3 4 1 , 4 1 2 ->= 2 2 1 , 4 2 ->= 2 4 , 4 1 2 ->= 2 4 1 , 2 1 ->= 1 4 , 2 1 4 ->= 1 4 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 4->0, 1->1, 2->2 }, it remains to prove termination of the 5-rule system { 0 1 2 ->= 2 2 1 , 0 2 ->= 2 0 , 0 1 2 ->= 2 0 1 , 2 1 ->= 1 0 , 2 1 0 ->= 1 0 2 } The system is trivially terminating.