/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) NonTerminationProof [COMPLETE, 417 ms]
(2) NO


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a(a(a(x1))) -> b(c(x1))
   c(b(x1)) -> a(a(a(a(c(x1)))))

Q is empty.

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(1) NonTerminationProof (COMPLETE)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure: 
"c b b b -> b c b b b c a c c a a c c a c c c"
c b b b -> b c b b b c a c c a a c c a c c c
by OverlapClosure OC 3"c b b b -> b c b b c b c a a c c a c c c
by OverlapClosure OC 3"c b b b -> b c b c b b c a c c c
by OverlapClosure OC 3"c b b b -> b c b c b c b c c
by OverlapClosure OC 3"c b b b -> b c a a a b c b c c
by OverlapClosure OC 2"c b -> b c a c
by OverlapClosure OC 3"c b -> a a a a c
by original rule (OC 1)""a a a -> b c
by original rule (OC 1)"""c b b -> a a b c b c c
by OverlapClosure OC 3"c b b -> a a a a a b c c
by OverlapClosure OC 2"c b -> a a a a c
by original rule (OC 1)""c b -> a b c c
by OverlapClosure OC 3"c b -> a a a a c
by original rule (OC 1)""a a a -> b c
by original rule (OC 1)""""a a a -> b c
by original rule (OC 1)""""a a a -> b c
by original rule (OC 1)"""c b -> b c a c
by OverlapClosure OC 3"c b -> a a a a c
by original rule (OC 1)""a a a -> b c
by original rule (OC 1)""""c b b -> b c b c a a c
by OverlapClosure OC 3"c b b -> b c a a a a a c
by OverlapClosure OC 2"c b -> b c a c
by OverlapClosure OC 3"c b -> a a a a c
by original rule (OC 1)""a a a -> b c
by original rule (OC 1)"""c b -> a a a a c
by original rule (OC 1)"""a a a -> b c
by original rule (OC 1)""""c b -> b c a c
by OverlapClosure OC 3"c b -> a a a a c
by original rule (OC 1)""a a a -> b c
by original rule (OC 1)""

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(2)
NO