/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { b->0, c->1, a->2 }, it remains to prove termination of the 2-rule system { 0 1 -> 2 0 0 , 0 2 -> 2 1 0 } The system was reversed. After renaming modulo { 1->0, 0->1, 2->2 }, it remains to prove termination of the 2-rule system { 0 1 -> 1 1 2 , 2 1 -> 1 0 2 } Loop of length 10 starting with a string of length 6 using right expansion and the encoding { 0->a, 1->b, ... }: .ab.bbbb rule ab-> bbc at position 0 .bbc.bbbb rule cb-> bac at position 2 .bbbac.bbb rule cb-> bac at position 4 .bbbabac.bb rule cb-> bac at position 6 .bbbababac.b rule ab-> bbc at position 5 .bbbabbbcac.b rule cb-> bac at position 9 .bbbabbbcabac. rule ab-> bbc at position 8 .bbbabbbcbbcac. rule cb-> bac at position 7 .bbbabbbbacbcac. rule cb-> bac at position 9 .bbbabbbbabaccac. rule ab-> bbc at position 8 .bbbabbbbbbcaccac.