/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { a->0, b->1, c->2 }, it remains to prove termination of the 4-rule system { 0 -> , 0 0 -> 1 1 2 , 1 -> , 2 1 -> 1 0 2 } Loop of length 15 starting with a string of length 8 using right expansion and the encoding { 0->a, 1->b, ... }: .aa.bbbbbb rule aa-> bbc at position 0 .bbc.bbbbbb rule cb-> bac at position 2 .bbbac.bbbbb rule cb-> bac at position 4 .bbbabac.bbbb rule b-> at position 4 .bbbaac.bbbb rule cb-> bac at position 5 .bbbaabac.bbb rule cb-> bac at position 7 .bbbaababac.bb rule b-> at position 7 .bbbaabaac.bb rule aa-> bbc at position 6 .bbbaabbbcc.bb rule cb-> bac at position 9 .bbbaabbbcbac.b rule cb-> bac at position 8 .bbbaabbbbacac.b rule a-> at position 11 .bbbaabbbbacc.b rule cb-> bac at position 11 .bbbaabbbbacbac. rule cb-> bac at position 10 .bbbaabbbbabacac. rule b-> at position 10 .bbbaabbbbaacac. rule aa-> bbc at position 9 .bbbaabbbbbbccac.