/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { a->0, b->1, c->2 }, it remains to prove termination of the 4-rule system { 0 -> , 0 1 -> 0 2 1 1 0 0 , 1 -> , 2 2 -> } The system was reversed. After renaming modulo { 0->0, 1->1, 2->2 }, it remains to prove termination of the 4-rule system { 0 -> , 1 0 -> 0 0 1 1 2 0 , 1 -> , 2 2 -> } Loop of length 7 starting with a string of length 4 using right expansion and the encoding { 0->a, 1->b, ... }: .ba.ca rule ba-> aabbca at position 0 .aabbca.ca rule a-> at position 5 .aabbc.ca rule cc-> at position 4 .aabb.a rule ba-> aabbca at position 3 .aabaabbca. rule a-> at position 3 .aababbca. rule b-> at position 4 .aababca. rule b-> at position 4 .aabaca.