/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) DependencyPairsProof [EQUIVALENT, 1 ms]
(2) QDP
(3) DependencyGraphProof [EQUIVALENT, 0 ms]
(4) QDP
(5) QDPOrderProof [EQUIVALENT, 108 ms]
(6) QDP
(7) PisEmptyProof [EQUIVALENT, 0 ms]
(8) YES


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a(b(x1)) -> x1
   a(c(x1)) -> b(c(c(a(a(b(x1))))))
   b(c(x1)) -> x1

Q is empty.

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(1) DependencyPairsProof (EQUIVALENT)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
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(2)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   A(c(x1)) -> B(c(c(a(a(b(x1))))))
   A(c(x1)) -> A(a(b(x1)))
   A(c(x1)) -> A(b(x1))
   A(c(x1)) -> B(x1)

The TRS R consists of the following rules:

   a(b(x1)) -> x1
   a(c(x1)) -> b(c(c(a(a(b(x1))))))
   b(c(x1)) -> x1

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(3) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes.
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(4)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   A(c(x1)) -> A(b(x1))
   A(c(x1)) -> A(a(b(x1)))

The TRS R consists of the following rules:

   a(b(x1)) -> x1
   a(c(x1)) -> b(c(c(a(a(b(x1))))))
   b(c(x1)) -> x1

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
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(5) QDPOrderProof (EQUIVALENT)
We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.

   A(c(x1)) -> A(b(x1))
   A(c(x1)) -> A(a(b(x1)))
The remaining pairs can at least be oriented weakly.
Used ordering:  Polynomial interpretation [POLO,RATPOLO]:

   POL(A(x_1)) = [1/2]x_1
   POL(a(x_1)) = [4]x_1
   POL(b(x_1)) = [1/4]x_1
   POL(c(x_1)) = [1/2] + [4]x_1
The value of delta used in the strict ordering is 1/4.
The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

   b(c(x1)) -> x1
   a(b(x1)) -> x1
   a(c(x1)) -> b(c(c(a(a(b(x1))))))


----------------------------------------

(6)
Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:

   a(b(x1)) -> x1
   a(c(x1)) -> b(c(c(a(a(b(x1))))))
   b(c(x1)) -> x1

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
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(7) PisEmptyProof (EQUIVALENT)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
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(8)
YES