/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


NO

After renaming modulo { a->0, b->1, c->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  0 1 0 2 -> 0 2 2 0 0 0 }


The system was reversed.

After renaming modulo { 0->0, 1->1, 2->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  2 0 1 0 -> 0 0 0 2 2 0 }


Loop of length 16 starting with a string of length 10
using right expansion and the encoding { 0->a, 1->b, ... }:

.caba.bababa
	rule caba-> aaacca at position 0
.aaacca.bababa
	rule caba-> aaacca at position 4
.aaacaaacca.baba
	rule a-> b at position 5
.aaacabacca.baba
	rule caba-> aaacca at position 8
.aaacabacaaacca.ba
	rule a-> b at position 9
.aaacabacabacca.ba
	rule caba-> aaacca at position 7
.aaacabaaaaccacca.ba
	rule a-> b at position 7
.aaacababaaccacca.ba
	rule a-> b at position 9
.aaacabababccacca.ba
	rule caba-> aaacca at position 14
.aaacabababccacaaacca.
	rule a-> b at position 15
.aaacabababccacabacca.
	rule caba-> aaacca at position 13
.aaacabababccaaaaccacca.
	rule a-> b at position 13
.aaacabababccabaaccacca.
	rule caba-> aaacca at position 11
.aaacabababcaaaccaaccacca.
	rule a-> b at position 12
.aaacabababcabaccaaccacca.
	rule caba-> aaacca at position 10
.aaacabababaaaccaccaaccacca.
	rule a-> b at position 11
.aaacababababaccaccaaccacca.