/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { a->0, b->1, c->2 }, it remains to prove termination of the 3-rule system { 0 -> , 0 1 -> 1 2 0 0 , 0 2 2 -> 1 0 } The system was reversed. After renaming modulo { 0->0, 1->1, 2->2 }, it remains to prove termination of the 3-rule system { 0 -> , 1 0 -> 0 0 2 1 , 2 2 0 -> 0 1 } Loop of length 24 starting with a string of length 8 using right expansion and the encoding { 0->a, 1->b, ... }: .ba.aaaaaa rule ba-> aacb at position 0 .aacb.aaaaaa rule ba-> aacb at position 3 .aacaacb.aaaaa rule a-> at position 3 .aacacb.aaaaa rule a-> at position 3 .aaccb.aaaaa rule ba-> aacb at position 4 .aaccaacb.aaaa rule cca-> ab at position 2 .aaabacb.aaaa rule ba-> aacb at position 6 .aaabacaacb.aaa rule a-> at position 6 .aaabacacb.aaa rule a-> at position 6 .aaabaccb.aaa rule ba-> aacb at position 7 .aaabaccaacb.aa rule cca-> ab at position 5 .aaabaabacb.aa rule ba-> aacb at position 6 .aaabaaaacbcb.aa rule ba-> aacb at position 11 .aaabaaaacbcaacb.a rule a-> at position 11 .aaabaaaacbcacb.a rule a-> at position 11 .aaabaaaacbccb.a rule ba-> aacb at position 12 .aaabaaaacbccaacb. rule cca-> ab at position 10 .aaabaaaacbabacb. rule ba-> aacb at position 9 .aaabaaaacaacbbacb. rule a-> at position 9 .aaabaaaacacbbacb. rule a-> at position 9 .aaabaaaaccbbacb. rule ba-> aacb at position 11 .aaabaaaaccbaacbcb. rule ba-> aacb at position 10 .aaabaaaaccaacbacbcb. rule cca-> ab at position 8 .aaabaaaaabacbacbcb. rule ba-> aacb at position 9 .aaabaaaaaaacbcbacbcb.