/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { a->0, b->1, c->2 }, it remains to prove termination of the 2-rule system { 0 -> 1 , 1 1 0 2 -> 0 2 2 0 0 0 } The system was reversed. After renaming modulo { 0->0, 1->1, 2->2 }, it remains to prove termination of the 2-rule system { 0 -> 1 , 2 0 1 1 -> 0 0 0 2 2 0 } Loop of length 24 starting with a string of length 10 using right expansion and the encoding { 0->a, 1->b, ... }: .cabb.bbbbbb rule cabb-> aaacca at position 0 .aaacca.bbbbbb rule cabb-> aaacca at position 4 .aaacaaacca.bbbb rule a-> b at position 5 .aaacabacca.bbbb rule a-> b at position 6 .aaacabbcca.bbbb rule cabb-> aaacca at position 8 .aaacabbcaaacca.bb rule a-> b at position 9 .aaacabbcabacca.bb rule a-> b at position 10 .aaacabbcabbcca.bb rule cabb-> aaacca at position 7 .aaacabbaaaccacca.bb rule a-> b at position 7 .aaacabbbaaccacca.bb rule a-> b at position 8 .aaacabbbbaccacca.bb rule a-> b at position 9 .aaacabbbbbccacca.bb rule cabb-> aaacca at position 14 .aaacabbbbbccacaaacca. rule a-> b at position 15 .aaacabbbbbccacabacca. rule a-> b at position 16 .aaacabbbbbccacabbcca. rule cabb-> aaacca at position 13 .aaacabbbbbccaaaaccacca. rule a-> b at position 13 .aaacabbbbbccabaaccacca. rule a-> b at position 14 .aaacabbbbbccabbaccacca. rule cabb-> aaacca at position 11 .aaacabbbbbcaaaccaaccacca. rule a-> b at position 12 .aaacabbbbbcabaccaaccacca. rule a-> b at position 13 .aaacabbbbbcabbccaaccacca. rule cabb-> aaacca at position 10 .aaacabbbbbaaaccaccaaccacca. rule a-> b at position 10 .aaacabbbbbbaaccaccaaccacca. rule a-> b at position 11 .aaacabbbbbbbaccaccaaccacca. rule a-> b at position 12 .aaacabbbbbbbbccaccaaccacca.