/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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NO

After renaming modulo { a->0, b->1, c->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  1 0 0 2 -> 0 2 2 0 0 0 }


The system was reversed.

After renaming modulo { 0->0, 1->1, 2->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  2 0 0 1 -> 0 0 0 2 2 0 }


Loop of length 16 starting with a string of length 10
using right expansion and the encoding { 0->a, 1->b, ... }:

.caab.ababab
	rule caab-> aaacca at position 0
.aaacca.ababab
	rule caab-> aaacca at position 4
.aaacaaacca.abab
	rule a-> b at position 6
.aaacaabcca.abab
	rule caab-> aaacca at position 8
.aaacaabcaaacca.ab
	rule a-> b at position 10
.aaacaabcaabcca.ab
	rule caab-> aaacca at position 7
.aaacaabaaaccacca.ab
	rule a-> b at position 8
.aaacaababaccacca.ab
	rule caab-> aaacca at position 14
.aaacaababaccacaaacca.
	rule a-> b at position 16
.aaacaababaccacaabcca.
	rule caab-> aaacca at position 13
.aaacaababaccaaaaccacca.
	rule a-> b at position 14
.aaacaababaccaabaccacca.
	rule caab-> aaacca at position 11
.aaacaababacaaaccaaccacca.
	rule a-> b at position 13
.aaacaababacaabccaaccacca.
	rule caab-> aaacca at position 10
.aaacaababaaaaccaccaaccacca.
	rule a-> b at position 10
.aaacaabababaaccaccaaccacca.
	rule a-> b at position 12
.aaacaababababccaccaaccacca.