/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


NO

After renaming modulo { a->0, b->1, c->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  1 1 1 2 -> 0 2 2 1 0 0 }


The system was reversed.

After renaming modulo { 0->0, 1->1, 2->2 }, 
it remains to prove termination of the 2-rule system
{ 0 -> 1 ,
  2 1 1 1 -> 0 0 1 2 2 0 }


Loop of length 26 starting with a string of length 10
using right expansion and the encoding { 0->a, 1->b, ... }:

.cbbb.bbbbbb
	rule cbbb-> aabcca at position 0
.aabcca.bbbbbb
	rule a-> b at position 5
.aabccb.bbbbbb
	rule cbbb-> aabcca at position 4
.aabcaabcca.bbbb
	rule a-> b at position 4
.aabcbabcca.bbbb
	rule a-> b at position 5
.aabcbbbcca.bbbb
	rule a-> b at position 9
.aabcbbbccb.bbbb
	rule cbbb-> aabcca at position 8
.aabcbbbcaabcca.bb
	rule a-> b at position 8
.aabcbbbcbabcca.bb
	rule a-> b at position 9
.aabcbbbcbbbcca.bb
	rule cbbb-> aabcca at position 7
.aabcbbbaabccacca.bb
	rule a-> b at position 7
.aabcbbbbabccacca.bb
	rule a-> b at position 8
.aabcbbbbbbccacca.bb
	rule a-> b at position 12
.aabcbbbbbbccbcca.bb
	rule a-> b at position 15
.aabcbbbbbbccbccb.bb
	rule cbbb-> aabcca at position 14
.aabcbbbbbbccbcaabcca.
	rule a-> b at position 14
.aabcbbbbbbccbcbabcca.
	rule a-> b at position 15
.aabcbbbbbbccbcbbbcca.
	rule cbbb-> aabcca at position 13
.aabcbbbbbbccbaabccacca.
	rule a-> b at position 13
.aabcbbbbbbccbbabccacca.
	rule a-> b at position 14
.aabcbbbbbbccbbbbccacca.
	rule cbbb-> aabcca at position 11
.aabcbbbbbbcaabccabccacca.
	rule a-> b at position 11
.aabcbbbbbbcbabccabccacca.
	rule a-> b at position 12
.aabcbbbbbbcbbbccabccacca.
	rule cbbb-> aabcca at position 10
.aabcbbbbbbaabccaccabccacca.
	rule a-> b at position 10
.aabcbbbbbbbabccaccabccacca.
	rule a-> b at position 11
.aabcbbbbbbbbbccaccabccacca.