/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 1 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(a(a(a(a(a(x1)))))))) -> a(a(a(a(a(a(b(b(a(b(b(x1))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(b(a(x1)))))))) -> b(b(a(b(b(a(a(a(a(a(a(x1))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(b(b(a(x1)))))))) -> b(b(a(b(b(a(a(a(a(a(a(x1))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(b(b(x))))))) -> b(b(a(b(b(a(a(a(a(a(x)))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(b(x))))))) -> b(b(a(b(b(a(a(a(a(a(x)))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(b(b(x))))))) -> b(b(a(b(b(a(a(a(a(a(x)))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 116, 117, 118, 119, 120, 121, 122, 123, 124 Node 95 is start node and node 96 is final node. Those nodes are connected through the following edges: * 95 to 97 labelled b_1(0)* 96 to 96 labelled #_1(0)* 97 to 98 labelled b_1(0)* 98 to 99 labelled a_1(0)* 99 to 100 labelled b_1(0)* 100 to 101 labelled b_1(0)* 101 to 102 labelled a_1(0)* 101 to 116 labelled b_1(1)* 102 to 103 labelled a_1(0)* 102 to 116 labelled b_1(1)* 103 to 104 labelled a_1(0)* 103 to 116 labelled b_1(1)* 104 to 105 labelled a_1(0)* 104 to 116 labelled b_1(1)* 105 to 96 labelled a_1(0)* 105 to 116 labelled b_1(1)* 116 to 117 labelled b_1(1)* 117 to 118 labelled a_1(1)* 118 to 119 labelled b_1(1)* 119 to 120 labelled b_1(1)* 120 to 121 labelled a_1(1)* 120 to 116 labelled b_1(1)* 121 to 122 labelled a_1(1)* 121 to 116 labelled b_1(1)* 122 to 123 labelled a_1(1)* 122 to 116 labelled b_1(1)* 123 to 124 labelled a_1(1)* 123 to 116 labelled b_1(1)* 124 to 96 labelled a_1(1)* 124 to 116 labelled b_1(1) ---------------------------------------- (6) YES