/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(a(b(a(b(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(b(a(x1)))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(b(a(b(a(x1)))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 331, 332, 333, 334, 335, 336, 337, 338, 339, 340, 341, 342, 343, 344, 357, 359, 360, 361, 362, 363, 364, 365, 366, 367, 368, 369 Node 331 is start node and node 332 is final node. Those nodes are connected through the following edges: * 331 to 333 labelled b_1(0)* 332 to 332 labelled #_1(0)* 333 to 334 labelled a_1(0)* 334 to 335 labelled b_1(0)* 335 to 336 labelled a_1(0)* 335 to 357 labelled b_1(1)* 336 to 337 labelled b_1(0)* 337 to 338 labelled a_1(0)* 338 to 339 labelled b_1(0)* 339 to 340 labelled a_1(0)* 340 to 341 labelled a_1(0)* 340 to 357 labelled b_1(1)* 341 to 342 labelled b_1(0)* 342 to 343 labelled a_1(0)* 342 to 357 labelled b_1(1)* 343 to 344 labelled b_1(0)* 344 to 332 labelled a_1(0)* 344 to 357 labelled b_1(1)* 357 to 359 labelled a_1(1)* 359 to 360 labelled b_1(1)* 360 to 361 labelled a_1(1)* 360 to 357 labelled b_1(1)* 361 to 362 labelled b_1(1)* 362 to 363 labelled a_1(1)* 363 to 364 labelled b_1(1)* 364 to 365 labelled a_1(1)* 365 to 366 labelled a_1(1)* 365 to 357 labelled b_1(1)* 366 to 367 labelled b_1(1)* 367 to 368 labelled a_1(1)* 367 to 357 labelled b_1(1)* 368 to 369 labelled b_1(1)* 369 to 332 labelled a_1(1)* 369 to 357 labelled b_1(1) ---------------------------------------- (6) YES