/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(b(a(a(b(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(b(a(a(b(b(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(b(a(a(x1)))))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(a(b(b(a(a(x1)))))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(a(b(b(a(x))))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(b(a(x))))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(a(b(b(a(x))))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 146, 147, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211, 212, 213, 214, 215, 216, 217, 218, 219, 220, 221, 222 Node 146 is start node and node 147 is final node. Those nodes are connected through the following edges: * 146 to 199 labelled b_1(0)* 147 to 147 labelled #_1(0)* 199 to 200 labelled a_1(0)* 200 to 201 labelled a_1(0)* 201 to 202 labelled b_1(0)* 202 to 203 labelled b_1(0)* 203 to 204 labelled a_1(0)* 204 to 205 labelled a_1(0)* 204 to 211 labelled b_1(1)* 205 to 206 labelled b_1(0)* 206 to 207 labelled a_1(0)* 206 to 211 labelled b_1(1)* 207 to 208 labelled b_1(0)* 208 to 209 labelled a_1(0)* 208 to 211 labelled b_1(1)* 209 to 210 labelled b_1(0)* 210 to 147 labelled a_1(0)* 210 to 211 labelled b_1(1)* 211 to 212 labelled a_1(1)* 212 to 213 labelled a_1(1)* 213 to 214 labelled b_1(1)* 214 to 215 labelled b_1(1)* 215 to 216 labelled a_1(1)* 216 to 217 labelled a_1(1)* 216 to 211 labelled b_1(1)* 217 to 218 labelled b_1(1)* 218 to 219 labelled a_1(1)* 218 to 211 labelled b_1(1)* 219 to 220 labelled b_1(1)* 220 to 221 labelled a_1(1)* 220 to 211 labelled b_1(1)* 221 to 222 labelled b_1(1)* 222 to 147 labelled a_1(1)* 222 to 211 labelled b_1(1) ---------------------------------------- (6) YES