/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 3 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 3, 4, 21, 22, 23, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143 Node 3 is start node and node 4 is final node. Those nodes are connected through the following edges: * 3 to 21 labelled b_1(0)* 4 to 4 labelled #_1(0)* 21 to 22 labelled a_1(0)* 22 to 23 labelled a_1(0)* 23 to 123 labelled b_1(0)* 123 to 124 labelled a_1(0)* 123 to 132 labelled b_1(1)* 124 to 125 labelled b_1(0)* 125 to 126 labelled a_1(0)* 125 to 132 labelled b_1(1)* 126 to 127 labelled b_1(0)* 127 to 128 labelled a_1(0)* 127 to 132 labelled b_1(1)* 128 to 129 labelled b_1(0)* 129 to 130 labelled a_1(0)* 129 to 132 labelled b_1(1)* 130 to 131 labelled b_1(0)* 131 to 4 labelled a_1(0)* 131 to 132 labelled b_1(1)* 132 to 133 labelled a_1(1)* 133 to 134 labelled a_1(1)* 134 to 135 labelled b_1(1)* 135 to 136 labelled a_1(1)* 135 to 132 labelled b_1(1)* 136 to 137 labelled b_1(1)* 137 to 138 labelled a_1(1)* 137 to 132 labelled b_1(1)* 138 to 139 labelled b_1(1)* 139 to 140 labelled a_1(1)* 139 to 132 labelled b_1(1)* 140 to 141 labelled b_1(1)* 141 to 142 labelled a_1(1)* 141 to 132 labelled b_1(1)* 142 to 143 labelled b_1(1)* 143 to 4 labelled a_1(1)* 143 to 132 labelled b_1(1) ---------------------------------------- (6) YES