/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(b(a(a(x1))))))))) -> a(a(a(b(a(a(b(a(a(a(a(b(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(a(a(a(a(b(a(x1))))))))) -> b(a(a(a(a(b(a(a(b(a(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(b(a(a(a(a(b(a(x1))))))))) -> b(a(a(a(a(b(a(a(b(a(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(b(a(a(a(a(b(x)))))))) -> b(a(a(a(a(b(a(a(b(a(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(a(a(a(a(b(x)))))))) -> b(a(a(a(a(b(a(a(b(a(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(b(a(a(a(a(b(x)))))))) -> b(a(a(a(a(b(a(a(b(a(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 461, 462, 463, 464, 465, 466, 467, 468, 469, 470, 471, 472, 473, 474, 475, 476, 477, 478, 479, 480, 481, 482 Node 461 is start node and node 462 is final node. Those nodes are connected through the following edges: * 461 to 463 labelled b_1(0)* 462 to 462 labelled #_1(0)* 463 to 464 labelled a_1(0)* 464 to 465 labelled a_1(0)* 465 to 466 labelled a_1(0)* 466 to 467 labelled a_1(0)* 467 to 468 labelled b_1(0)* 468 to 469 labelled a_1(0)* 468 to 473 labelled b_1(1)* 469 to 470 labelled a_1(0)* 470 to 471 labelled b_1(0)* 471 to 472 labelled a_1(0)* 471 to 473 labelled b_1(1)* 472 to 462 labelled a_1(0)* 472 to 473 labelled b_1(1)* 473 to 474 labelled a_1(1)* 474 to 475 labelled a_1(1)* 475 to 476 labelled a_1(1)* 476 to 477 labelled a_1(1)* 477 to 478 labelled b_1(1)* 478 to 479 labelled a_1(1)* 478 to 473 labelled b_1(1)* 479 to 480 labelled a_1(1)* 480 to 481 labelled b_1(1)* 481 to 482 labelled a_1(1)* 481 to 473 labelled b_1(1)* 482 to 462 labelled a_1(1)* 482 to 473 labelled b_1(1) ---------------------------------------- (6) YES