/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 4 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 184, 185, 186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208, 209 Node 184 is start node and node 185 is final node. Those nodes are connected through the following edges: * 184 to 186 labelled b_1(0)* 185 to 185 labelled #_1(0)* 186 to 187 labelled a_1(0)* 187 to 188 labelled b_1(0)* 188 to 189 labelled a_1(0)* 189 to 190 labelled a_1(0)* 190 to 191 labelled b_1(0)* 191 to 192 labelled a_1(0)* 192 to 193 labelled b_1(0)* 193 to 194 labelled a_1(0)* 193 to 198 labelled b_1(1)* 194 to 195 labelled b_1(0)* 195 to 196 labelled a_1(0)* 195 to 198 labelled b_1(1)* 196 to 197 labelled b_1(0)* 197 to 185 labelled a_1(0)* 197 to 198 labelled b_1(1)* 198 to 199 labelled a_1(1)* 199 to 200 labelled b_1(1)* 200 to 201 labelled a_1(1)* 201 to 202 labelled a_1(1)* 202 to 203 labelled b_1(1)* 203 to 204 labelled a_1(1)* 204 to 205 labelled b_1(1)* 205 to 206 labelled a_1(1)* 205 to 198 labelled b_1(1)* 206 to 207 labelled b_1(1)* 207 to 208 labelled a_1(1)* 207 to 198 labelled b_1(1)* 208 to 209 labelled b_1(1)* 209 to 185 labelled a_1(1)* 209 to 198 labelled b_1(1) ---------------------------------------- (6) YES