/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


NO

After renaming modulo { 0->0, 1->1 }, 
it remains to prove termination of the 2-rule system
{ 0 0 0 0 -> 0 1 0 1 ,
  1 0 0 1 -> 0 1 0 0 }


The system was reversed.

After renaming modulo { 0->0, 1->1 }, 
it remains to prove termination of the 2-rule system
{ 0 0 0 0 -> 1 0 1 0 ,
  1 0 0 1 -> 0 0 1 0 }


Loop of length 27 starting with a string of length 15
using right expansion and the encoding { 0->a, 1->b, ... }:

.aaaa.ababbababaa
	rule aaaa-> baba at position 0
.baba.ababbababaa
	rule baab-> aaba at position 2
.baaaba.abbababaa
	rule baab-> aaba at position 4
.baaaaaba.bababaa
	rule aaaa-> baba at position 1
.bbabaaba.bababaa
	rule baab-> aaba at position 3
.bbaaabaa.bababaa
	rule baab-> aaba at position 5
.bbaaaaaba.ababaa
	rule aaaa-> baba at position 2
.bbbabaaba.ababaa
	rule baab-> aaba at position 7
.bbbabaaaaba.abaa
	rule baab-> aaba at position 9
.bbbabaaaaaaba.aa
	rule aaaa-> baba at position 7
.bbbabaabababa.aa
	rule baab-> aaba at position 4
.bbbaaabaababa.aa
	rule baab-> aaba at position 6
.bbbaaaaabaaba.aa
	rule baab-> aaba at position 8
.bbbaaaaaaabaa.aa
	rule aaaa-> baba at position 5
.bbbaababaabaa.aa
	rule baab-> aaba at position 2
.bbaabaabaabaa.aa
	rule baab-> aaba at position 1
.baabaaabaabaa.aa
	rule baab-> aaba at position 0
.aabaaaabaabaa.aa
	rule baab-> aaba at position 7
.aabaaaaaabaaa.aa
	rule aaaa-> baba at position 5
.aabaabababaaa.aa
	rule baab-> aaba at position 2
.aaaabaababaaa.aa
	rule baab-> aaba at position 4
.aaaaaabaabaaa.aa
	rule baab-> aaba at position 6
.aaaaaaaabaaaa.aa
	rule aaaa-> baba at position 11
.aaaaaaaabaababa.
	rule baab-> aaba at position 8
.aaaaaaaaaabaaba.
	rule aaaa-> baba at position 5
.aaaaababaabaaba.
	rule baab-> aaba at position 10
.aaaaababaaaabaa.
	rule aaaa-> baba at position 8
.aaaaababbababaa.