/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 b(c(x1)) -> a(x1)
 b(b(x1)) -> a(c(x1))
 a(x1) -> c(b(x1))
 c(c(c(x1))) -> b(x1)

Proof:
 String Reversal Processor:
  c(b(x1)) -> a(x1)
  b(b(x1)) -> c(a(x1))
  a(x1) -> b(c(x1))
  c(c(c(x1))) -> b(x1)
  WPO Processor:
   algebra: Sum
   weight function:
    w0 = 0
    w(a) = 4
    w(b) = 3
    w(c) = 1
   status function:
    st(a) = st(b) = st(c) = [0]
   precedence:
    c > a > b
   problem:
    
   Qed