/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { a->0, b->1 }, it remains to prove termination of the 2-rule system { 0 0 0 -> 1 0 1 , 1 0 1 -> 0 1 0 } The system was reversed. After renaming modulo { 0->0, 1->1 }, it remains to prove termination of the 2-rule system { 0 0 0 -> 1 0 1 , 1 0 1 -> 0 1 0 } Loop of length 6 starting with a string of length 6 using right expansion and the encoding { 0->a, 1->b, ... }: .aaa.baa rule aaa-> bab at position 0 .bab.baa rule bab-> aba at position 0 .aba.baa rule bab-> aba at position 1 .aaba.aa rule aaa-> bab at position 3 .aabbab. rule bab-> aba at position 3 .aababa. rule bab-> aba at position 2 .aaabaa.