/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: f(f(x1)) -> b(b(b(x1))) a(f(x1)) -> f(a(a(x1))) b(b(x1)) -> c(c(a(c(x1)))) d(b(x1)) -> d(a(b(x1))) c(c(x1)) -> d(d(d(x1))) b(d(x1)) -> d(b(x1)) c(d(d(x1))) -> f(x1) Proof: Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0 + 4, [b](x0) = x0 + 9, [c](x0) = x0 + 6, [f](x0) = x0 + 14, [a](x0) = x0 orientation: f(f(x1)) = x1 + 28 >= x1 + 27 = b(b(b(x1))) a(f(x1)) = x1 + 14 >= x1 + 14 = f(a(a(x1))) b(b(x1)) = x1 + 18 >= x1 + 18 = c(c(a(c(x1)))) d(b(x1)) = x1 + 13 >= x1 + 13 = d(a(b(x1))) c(c(x1)) = x1 + 12 >= x1 + 12 = d(d(d(x1))) b(d(x1)) = x1 + 13 >= x1 + 13 = d(b(x1)) c(d(d(x1))) = x1 + 14 >= x1 + 14 = f(x1) problem: a(f(x1)) -> f(a(a(x1))) b(b(x1)) -> c(c(a(c(x1)))) d(b(x1)) -> d(a(b(x1))) c(c(x1)) -> d(d(d(x1))) b(d(x1)) -> d(b(x1)) c(d(d(x1))) -> f(x1) String Reversal Processor: f(a(x1)) -> a(a(f(x1))) b(b(x1)) -> c(a(c(c(x1)))) b(d(x1)) -> b(a(d(x1))) c(c(x1)) -> d(d(d(x1))) d(b(x1)) -> b(d(x1)) d(d(c(x1))) -> f(x1) Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0, [b](x0) = 4x0 + 1, [c](x0) = x0, [f](x0) = x0, [a](x0) = x0 orientation: f(a(x1)) = x1 >= x1 = a(a(f(x1))) b(b(x1)) = 16x1 + 5 >= x1 = c(a(c(c(x1)))) b(d(x1)) = 4x1 + 1 >= 4x1 + 1 = b(a(d(x1))) c(c(x1)) = x1 >= x1 = d(d(d(x1))) d(b(x1)) = 4x1 + 1 >= 4x1 + 1 = b(d(x1)) d(d(c(x1))) = x1 >= x1 = f(x1) problem: f(a(x1)) -> a(a(f(x1))) b(d(x1)) -> b(a(d(x1))) c(c(x1)) -> d(d(d(x1))) d(b(x1)) -> b(d(x1)) d(d(c(x1))) -> f(x1) Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0 + 2, [b](x0) = x0 + 8, [c](x0) = x0 + 3, [f](x0) = x0, [a](x0) = x0 orientation: f(a(x1)) = x1 >= x1 = a(a(f(x1))) b(d(x1)) = x1 + 10 >= x1 + 10 = b(a(d(x1))) c(c(x1)) = x1 + 6 >= x1 + 6 = d(d(d(x1))) d(b(x1)) = x1 + 10 >= x1 + 10 = b(d(x1)) d(d(c(x1))) = x1 + 7 >= x1 = f(x1) problem: f(a(x1)) -> a(a(f(x1))) b(d(x1)) -> b(a(d(x1))) c(c(x1)) -> d(d(d(x1))) d(b(x1)) -> b(d(x1)) Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0, [b](x0) = 8x0 + 4, [c](x0) = x0 + 1, [f](x0) = x0 + 4, [a](x0) = x0 orientation: f(a(x1)) = x1 + 4 >= x1 + 4 = a(a(f(x1))) b(d(x1)) = 8x1 + 4 >= 8x1 + 4 = b(a(d(x1))) c(c(x1)) = x1 + 2 >= x1 = d(d(d(x1))) d(b(x1)) = 8x1 + 4 >= 8x1 + 4 = b(d(x1)) problem: f(a(x1)) -> a(a(f(x1))) b(d(x1)) -> b(a(d(x1))) d(b(x1)) -> b(d(x1)) Bounds Processor: bound: 1 enrichment: match automaton: final states: {8,5,1} transitions: f50() -> 2* a1(14) -> 15* f0(2) -> 3* b1(15) -> 16* d0(2) -> 6* b0(6) -> 8* b0(7) -> 5* d1(13) -> 14* a0(6) -> 7* a0(4) -> 1* a0(3) -> 4* 16 -> 8* 2 -> 13* 8 -> 14,6 1 -> 3* problem: Qed