/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo { 1->0, 4->1, 3->2, 2->3, 5->4, 6->5 }, it remains to prove termination of the 9-rule system { 0 0 -> 1 2 , 0 3 -> 3 0 , 3 3 -> 0 0 0 , 2 2 -> 4 5 , 2 1 -> 0 0 , 1 1 -> 2 , 4 4 -> 5 3 , 4 5 -> 0 3 , 5 5 -> 3 0 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 85 | | 0 1 | \ / 1 is interpreted by / \ | 1 57 | | 0 1 | \ / 2 is interpreted by / \ | 1 113 | | 0 1 | \ / 3 is interpreted by / \ | 1 128 | | 0 1 | \ / 4 is interpreted by / \ | 1 118 | | 0 1 | \ / 5 is interpreted by / \ | 1 107 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, it remains to prove termination of the 3-rule system { 0 0 -> 1 2 , 0 3 -> 3 0 , 2 1 -> 0 0 } Applying sparse untiling TRFCU(2) after reversal [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo { 0->0, 1->1, 2->2 }, it remains to prove termination of the 2-rule system { 0 0 -> 1 2 , 2 1 -> 0 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (0,false)->1, (2,true)->2, (1,false)->3, (2,false)->4 }, it remains to prove termination of the 5-rule system { 0 1 -> 2 , 2 3 -> 0 1 , 2 3 -> 0 , 1 1 ->= 3 4 , 4 3 ->= 1 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 2->0, 3->1, 0->2, 1->3, 4->4 }, it remains to prove termination of the 3-rule system { 0 1 -> 2 3 , 3 3 ->= 1 4 , 4 1 ->= 3 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 3->0, 1->1, 4->2 }, it remains to prove termination of the 2-rule system { 0 0 ->= 1 2 , 2 1 ->= 0 0 } The system is trivially terminating.