/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo { c->0, b->1, a->2 }, it remains to prove termination of the 1-rule system { 0 1 2 1 2 -> 2 1 2 1 2 1 0 1 0 } The system was reversed. After renaming modulo { 2->0, 1->1, 0->2 }, it remains to prove termination of the 1-rule system { 0 1 0 1 2 -> 2 1 2 1 0 1 0 1 0 } Loop of length 4 starting with a string of length 11 using right expansion and the encoding { 0->a, 1->b, ... }: .ababc.babcbc rule ababc-> cbcbababa at position 0 .cbcbababa.babcbc rule ababc-> cbcbababa at position 8 .cbcbababcbcbababa.bc rule ababc-> cbcbababa at position 4 .cbcbcbcbabababcbababa.bc rule ababc-> cbcbababa at position 18 .cbcbcbcbabababcbabcbcbababa.