/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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NO

After renaming modulo { a->0, b->1, c->2 }, 
it remains to prove termination of the 4-rule system
{ 0 -> ,
  0 1 -> 1 0 2 1 0 ,
  1 -> ,
  2 2 -> }


The system was reversed.

After renaming modulo { 0->0, 1->1, 2->2 }, 
it remains to prove termination of the 4-rule system
{ 0 -> ,
  1 0 -> 0 1 2 0 1 ,
  1 -> ,
  2 2 -> }


Loop of length 12 starting with a string of length 6
using right expansion and the encoding { 0->a, 1->b, ... }:

.ba.aaca
	rule ba-> abcab at position 0
.abcab.aaca
	rule a->  at position 3
.abcb.aaca
	rule ba-> abcab at position 3
.abcabcab.aca
	rule a->  at position 3
.abcbcab.aca
	rule b->  at position 3
.abccab.aca
	rule cc->  at position 2
.abab.aca
	rule ba-> abcab at position 3
.abaabcab.ca
	rule a->  at position 6
.abaabcb.ca
	rule b->  at position 6
.abaabc.ca
	rule cc->  at position 5
.abaab.a
	rule ba-> abcab at position 4
.abaaabcab.
	rule b->  at position 5
.abaaacab.