/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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NO

After renaming modulo { b->0, a->1, c->2 }, 
it remains to prove termination of the 6-rule system
{ 0 0 1 -> 0 1 1 ,
  2 2 1 -> 2 0 2 ,
  2 0 2 ->= 0 1 1 ,
  2 2 2 ->= 2 1 1 ,
  1 0 0 ->= 0 2 2 ,
  2 1 1 ->= 0 1 0 }


Loop of length 23 starting with a string of length 9
using right expansion and the encoding { 0->a, 1->b, ... }:

.aab.aacacb
	rule aab-> abb at position 0
.abb.aacacb
	rule baa->= acc at position 2
.abacc.cacb
	rule ccc->= cbb at position 3
.abacbb.acb
	rule cbb->= aba at position 3
.abaaba.acb
	rule aab-> abb at position 2
.ababba.acb
	rule baa->= acc at position 4
.ababacc.cb
	rule ccc->= cbb at position 5
.ababacbb.b
	rule cbb->= aba at position 5
.ababaaba.b
	rule baa->= acc at position 3
.abaaccba.b
	rule baa->= acc at position 1
.aaccccba.b
	rule ccb-> cac at position 4
.aacccaca.b
	rule ccc->= cbb at position 2
.aacbbaca.b
	rule cbb->= aba at position 2
.aaabaaca.b
	rule aab-> abb at position 1
.aabbaaca.b
	rule baa->= acc at position 3
.aabaccca.b
	rule ccc->= cbb at position 4
.aabacbba.b
	rule cbb->= aba at position 4
.aabaabaa.b
	rule aab-> abb at position 3
.aababbaa.b
	rule baa->= acc at position 5
.aababacc.b
	rule ccb-> cac at position 6
.aababacac.
	rule cac->= abb at position 6
.aababaabb.
	rule baa->= acc at position 4
.aabaaccbb.
	rule ccb-> cac at position 5
.aabaacacb.