/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: b(b(b(x1))) -> b(a(c(x1))) a(a(c(x1))) -> b(b(a(x1))) weak: a(b(c(x1))) -> c(b(a(x1))) b(b(a(x1))) -> c(b(c(x1))) c(a(c(x1))) -> a(b(c(x1))) a(b(b(x1))) -> c(b(a(x1))) Proof: Arctic Interpretation Processor: dimension: 2 interpretation: [2 -&] [c](x0) = [3 -&]x0, [0 1] [b](x0) = [6 2]x0, [5 -&] [a](x0) = [6 -&]x0 orientation: [9 8 ] [9 -&] b(b(b(x1))) = [13 9 ]x1 >= [13 -&]x1 = b(a(c(x1))) [12 -&] [12 -&] a(a(c(x1))) = [13 -&]x1 >= [13 -&]x1 = b(b(a(x1))) [9 -&] [9 -&] a(b(c(x1))) = [10 -&]x1 >= [10 -&]x1 = c(b(a(x1))) [12 -&] [6 -&] b(b(a(x1))) = [13 -&]x1 >= [7 -&]x1 = c(b(c(x1))) [9 -&] [9 -&] c(a(c(x1))) = [10 -&]x1 >= [10 -&]x1 = a(b(c(x1))) [12 8 ] [9 -&] a(b(b(x1))) = [13 9 ]x1 >= [10 -&]x1 = c(b(a(x1))) problem: strict: b(b(b(x1))) -> b(a(c(x1))) a(a(c(x1))) -> b(b(a(x1))) weak: a(b(c(x1))) -> c(b(a(x1))) c(a(c(x1))) -> a(b(c(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [c](x0) = 8x0, [b](x0) = 4x0, [a](x0) = x0 orientation: b(b(b(x1))) = 12x1 >= 12x1 = b(a(c(x1))) a(a(c(x1))) = 8x1 >= 8x1 = b(b(a(x1))) a(b(c(x1))) = 12x1 >= 12x1 = c(b(a(x1))) c(a(c(x1))) = 16x1 >= 12x1 = a(b(c(x1))) problem: strict: b(b(b(x1))) -> b(a(c(x1))) a(a(c(x1))) -> b(b(a(x1))) weak: a(b(c(x1))) -> c(b(a(x1))) String Reversal Processor: strict: b(b(b(x1))) -> c(a(b(x1))) c(a(a(x1))) -> a(b(b(x1))) weak: c(b(a(x1))) -> a(b(c(x1))) Bounds Processor: bound: 1 enrichment: match-rt automaton: final states: {4} transitions: c1(11) -> 12* b1(9) -> 10* a1(10) -> 11* b0(4) -> 4* a0(4) -> 4* c0(4) -> 4* 12 -> 10,4 4 -> 9* problem: strict: c(a(a(x1))) -> a(b(b(x1))) weak: c(b(a(x1))) -> a(b(c(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [c](x0) = 1x0, [b](x0) = x0, [a](x0) = 2x0 orientation: c(a(a(x1))) = 5x1 >= 2x1 = a(b(b(x1))) c(b(a(x1))) = 3x1 >= 3x1 = a(b(c(x1))) problem: strict: weak: c(b(a(x1))) -> a(b(c(x1))) Qed