/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo { c->0, a->1, b->2 }, it remains to prove termination of the 6-rule system { 0 0 1 -> 2 1 0 , 2 2 2 -> 1 1 1 , 0 1 2 ->= 1 1 1 , 0 1 2 ->= 1 0 1 , 0 2 0 ->= 0 2 2 , 2 1 2 ->= 2 2 0 } Applying context closure of depth 1 in the following form: System R over Sigma maps to { fold(xly) -> fold(xry) | l -> r in R, x,y in Sigma } over Sigma^2, where fold(a_1...a_n) = (a_1,a_2)...(a_{n-1},a_{n}) After renaming modulo { [0, 0]->0, [0, 1]->1, [1, 0]->2, [0, 2]->3, [2, 1]->4, [2, 2]->5, [2, 0]->6, [1, 1]->7, [1, 2]->8 }, it remains to prove termination of the 54-rule system { 0 0 1 2 -> 3 4 2 0 , 3 5 5 6 -> 1 7 7 2 , 0 1 8 6 ->= 1 7 7 2 , 0 1 8 6 ->= 1 2 1 2 , 0 3 6 0 ->= 0 3 5 6 , 3 4 8 6 ->= 3 5 6 0 , 0 0 1 7 -> 3 4 2 1 , 3 5 5 4 -> 1 7 7 7 , 0 1 8 4 ->= 1 7 7 7 , 0 1 8 4 ->= 1 2 1 7 , 0 3 6 1 ->= 0 3 5 4 , 3 4 8 4 ->= 3 5 6 1 , 0 0 1 8 -> 3 4 2 3 , 3 5 5 5 -> 1 7 7 8 , 0 1 8 5 ->= 1 7 7 8 , 0 1 8 5 ->= 1 2 1 8 , 0 3 6 3 ->= 0 3 5 5 , 3 4 8 5 ->= 3 5 6 3 , 2 0 1 2 -> 8 4 2 0 , 8 5 5 6 -> 7 7 7 2 , 2 1 8 6 ->= 7 7 7 2 , 2 1 8 6 ->= 7 2 1 2 , 2 3 6 0 ->= 2 3 5 6 , 8 4 8 6 ->= 8 5 6 0 , 2 0 1 7 -> 8 4 2 1 , 8 5 5 4 -> 7 7 7 7 , 2 1 8 4 ->= 7 7 7 7 , 2 1 8 4 ->= 7 2 1 7 , 2 3 6 1 ->= 2 3 5 4 , 8 4 8 4 ->= 8 5 6 1 , 2 0 1 8 -> 8 4 2 3 , 8 5 5 5 -> 7 7 7 8 , 2 1 8 5 ->= 7 7 7 8 , 2 1 8 5 ->= 7 2 1 8 , 2 3 6 3 ->= 2 3 5 5 , 8 4 8 5 ->= 8 5 6 3 , 6 0 1 2 -> 5 4 2 0 , 5 5 5 6 -> 4 7 7 2 , 6 1 8 6 ->= 4 7 7 2 , 6 1 8 6 ->= 4 2 1 2 , 6 3 6 0 ->= 6 3 5 6 , 5 4 8 6 ->= 5 5 6 0 , 6 0 1 7 -> 5 4 2 1 , 5 5 5 4 -> 4 7 7 7 , 6 1 8 4 ->= 4 7 7 7 , 6 1 8 4 ->= 4 2 1 7 , 6 3 6 1 ->= 6 3 5 4 , 5 4 8 4 ->= 5 5 6 1 , 6 0 1 8 -> 5 4 2 3 , 5 5 5 5 -> 4 7 7 8 , 6 1 8 5 ->= 4 7 7 8 , 6 1 8 5 ->= 4 2 1 8 , 6 3 6 3 ->= 6 3 5 5 , 5 4 8 5 ->= 5 5 6 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 1 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 4 is interpreted by / \ | 1 0 0 1 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 6 is interpreted by / \ | 1 0 1 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 1 0 0 0 | \ / 7 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 8 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 1 | | 0 0 0 0 0 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5, 6->6, 7->7, 8->8 }, it remains to prove termination of the 49-rule system { 0 0 1 2 -> 3 4 2 0 , 3 5 5 6 -> 1 7 7 2 , 0 1 8 6 ->= 1 7 7 2 , 0 1 8 6 ->= 1 2 1 2 , 0 3 6 0 ->= 0 3 5 6 , 0 0 1 7 -> 3 4 2 1 , 3 5 5 4 -> 1 7 7 7 , 0 1 8 4 ->= 1 7 7 7 , 0 1 8 4 ->= 1 2 1 7 , 0 3 6 1 ->= 0 3 5 4 , 3 4 8 4 ->= 3 5 6 1 , 0 0 1 8 -> 3 4 2 3 , 3 5 5 5 -> 1 7 7 8 , 0 1 8 5 ->= 1 7 7 8 , 0 1 8 5 ->= 1 2 1 8 , 0 3 6 3 ->= 0 3 5 5 , 3 4 8 5 ->= 3 5 6 3 , 2 0 1 2 -> 8 4 2 0 , 8 5 5 6 -> 7 7 7 2 , 2 1 8 6 ->= 7 7 7 2 , 2 1 8 6 ->= 7 2 1 2 , 2 3 6 0 ->= 2 3 5 6 , 2 0 1 7 -> 8 4 2 1 , 8 5 5 4 -> 7 7 7 7 , 2 1 8 4 ->= 7 7 7 7 , 2 1 8 4 ->= 7 2 1 7 , 2 3 6 1 ->= 2 3 5 4 , 8 4 8 4 ->= 8 5 6 1 , 2 0 1 8 -> 8 4 2 3 , 8 5 5 5 -> 7 7 7 8 , 2 1 8 5 ->= 7 7 7 8 , 2 1 8 5 ->= 7 2 1 8 , 2 3 6 3 ->= 2 3 5 5 , 8 4 8 5 ->= 8 5 6 3 , 6 0 1 2 -> 5 4 2 0 , 5 5 5 6 -> 4 7 7 2 , 6 3 6 0 ->= 6 3 5 6 , 6 0 1 7 -> 5 4 2 1 , 5 5 5 4 -> 4 7 7 7 , 6 1 8 4 ->= 4 7 7 7 , 6 1 8 4 ->= 4 2 1 7 , 6 3 6 1 ->= 6 3 5 4 , 5 4 8 4 ->= 5 5 6 1 , 6 0 1 8 -> 5 4 2 3 , 5 5 5 5 -> 4 7 7 8 , 6 1 8 5 ->= 4 7 7 8 , 6 1 8 5 ->= 4 2 1 8 , 6 3 6 3 ->= 6 3 5 5 , 5 4 8 5 ->= 5 5 6 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 0 | | 0 1 | \ / 7 is interpreted by / \ | 1 0 | | 0 1 | \ / 8 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 3->0, 5->1, 6->2, 1->3, 7->4, 2->5, 4->6, 0->7, 8->8 }, it remains to prove termination of the 33-rule system { 0 1 1 2 -> 3 4 4 5 , 0 1 1 6 -> 3 4 4 4 , 7 0 2 3 ->= 7 0 1 6 , 0 6 8 6 ->= 0 1 2 3 , 0 1 1 1 -> 3 4 4 8 , 7 0 2 0 ->= 7 0 1 1 , 0 6 8 1 ->= 0 1 2 0 , 5 7 3 5 -> 8 6 5 7 , 8 1 1 2 -> 4 4 4 5 , 5 3 8 2 ->= 4 4 4 5 , 5 3 8 2 ->= 4 5 3 5 , 8 1 1 6 -> 4 4 4 4 , 5 3 8 6 ->= 4 4 4 4 , 5 3 8 6 ->= 4 5 3 4 , 5 0 2 3 ->= 5 0 1 6 , 8 6 8 6 ->= 8 1 2 3 , 8 1 1 1 -> 4 4 4 8 , 5 3 8 1 ->= 4 4 4 8 , 5 3 8 1 ->= 4 5 3 8 , 5 0 2 0 ->= 5 0 1 1 , 8 6 8 1 ->= 8 1 2 0 , 2 7 3 5 -> 1 6 5 7 , 1 1 1 2 -> 6 4 4 5 , 1 1 1 6 -> 6 4 4 4 , 2 3 8 6 ->= 6 4 4 4 , 2 3 8 6 ->= 6 5 3 4 , 2 0 2 3 ->= 2 0 1 6 , 1 6 8 6 ->= 1 1 2 3 , 1 1 1 1 -> 6 4 4 8 , 2 3 8 1 ->= 6 4 4 8 , 2 3 8 1 ->= 6 5 3 8 , 2 0 2 0 ->= 2 0 1 1 , 1 6 8 1 ->= 1 1 2 0 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 1 | | 0 1 | \ / 6 is interpreted by / \ | 1 1 | | 0 1 | \ / 7 is interpreted by / \ | 1 0 | | 0 1 | \ / 8 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 7->0, 0->1, 2->2, 3->3, 1->4, 6->5, 8->6, 5->7 }, it remains to prove termination of the 15-rule system { 0 1 2 3 ->= 0 1 4 5 , 1 5 6 5 ->= 1 4 2 3 , 0 1 2 1 ->= 0 1 4 4 , 1 5 6 4 ->= 1 4 2 1 , 7 0 3 7 -> 6 5 7 0 , 7 1 2 3 ->= 7 1 4 5 , 6 5 6 5 ->= 6 4 2 3 , 7 1 2 1 ->= 7 1 4 4 , 6 5 6 4 ->= 6 4 2 1 , 2 0 3 7 -> 4 5 7 0 , 2 1 2 3 ->= 2 1 4 5 , 4 5 6 5 ->= 4 4 2 3 , 2 3 6 4 ->= 5 7 3 6 , 2 1 2 1 ->= 2 1 4 4 , 4 5 6 4 ->= 4 4 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 0 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 2 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 2 | | 0 1 | \ / 7 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 1->0, 5->1, 6->2, 4->3, 2->4, 3->5, 7->6, 0->7 }, it remains to prove termination of the 5-rule system { 0 1 2 1 ->= 0 3 4 5 , 6 7 5 6 -> 2 1 6 7 , 2 1 2 1 ->= 2 3 4 5 , 3 1 2 1 ->= 3 3 4 5 , 4 5 2 3 ->= 1 6 5 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 4 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 1 | | 0 0 0 0 0 | \ / 6 is interpreted by / \ | 1 0 1 1 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 1 0 0 0 | \ / 7 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5, 6->6 }, it remains to prove termination of the 4-rule system { 0 1 2 1 ->= 0 3 4 5 , 2 1 2 1 ->= 2 3 4 5 , 3 1 2 1 ->= 3 3 4 5 , 4 5 2 3 ->= 1 6 5 2 } The system is trivially terminating.