/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES

Problem:
 strict:
  a(a(c(x1))) -> c(c(c(x1)))
  a(c(b(x1))) -> a(a(c(x1)))
  b(c(a(x1))) -> b(a(b(x1)))
  a(b(c(x1))) -> b(a(c(x1)))
 weak:
  b(c(b(x1))) -> a(b(c(x1)))
  a(c(b(x1))) -> c(c(b(x1)))

Proof:
 Arctic Interpretation Processor:
  dimension: 2
  interpretation:
             [0  1 ]  
   [a](x0) = [-& 0 ]x0,
   
             [0  -&]  
   [c](x0) = [1  0 ]x0,
   
             [0  1 ]  
   [b](x0) = [-& -&]x0
  orientation:
                 [2 1]      [0  -&]                
   a(a(c(x1))) = [1 0]x1 >= [1  0 ]x1 = c(c(c(x1)))
   
                 [2 3]      [2 1]                
   a(c(b(x1))) = [1 2]x1 >= [1 0]x1 = a(a(c(x1)))
   
                 [2  3 ]      [0  1 ]                
   b(c(a(x1))) = [-& -&]x1 >= [-& -&]x1 = b(a(b(x1)))
   
                 [2  1 ]      [2  1 ]                
   a(b(c(x1))) = [-& -&]x1 >= [-& -&]x1 = b(a(c(x1)))
   
                 [2  3 ]      [2  1 ]                
   b(c(b(x1))) = [-& -&]x1 >= [-& -&]x1 = a(b(c(x1)))
   
                 [2 3]      [0 1]                
   a(c(b(x1))) = [1 2]x1 >= [1 2]x1 = c(c(b(x1)))
  problem:
   strict:
    a(a(c(x1))) -> c(c(c(x1)))
    a(c(b(x1))) -> a(a(c(x1)))
    a(b(c(x1))) -> b(a(c(x1)))
   weak:
    b(c(b(x1))) -> a(b(c(x1)))
    a(c(b(x1))) -> c(c(b(x1)))
  String Reversal Processor:
   strict:
    c(a(a(x1))) -> c(c(c(x1)))
    b(c(a(x1))) -> c(a(a(x1)))
    c(b(a(x1))) -> c(a(b(x1)))
   weak:
    b(c(b(x1))) -> c(b(a(x1)))
    b(c(a(x1))) -> b(c(c(x1)))
   LPO Processor:
    precedence:
     b > a ~ c
    problem:
     strict:
      c(a(a(x1))) -> c(c(c(x1)))
     weak:
      b(c(a(x1))) -> b(c(c(x1)))
    String Reversal Processor:
     strict:
      a(a(c(x1))) -> c(c(c(x1)))
     weak:
      a(c(b(x1))) -> c(c(b(x1)))
     Arctic Interpretation Processor:
      dimension: 1
      interpretation:
       [a](x0) = 1x0,
       
       [c](x0) = x0,
       
       [b](x0) = x0
      orientation:
       a(a(c(x1))) = 2x1 >= x1 = c(c(c(x1)))
       
       a(c(b(x1))) = 1x1 >= x1 = c(c(b(x1)))
      problem:
       strict:
        
       weak:
        
      Qed