/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given RelTRS could be proven: (0) RelTRS (1) RelTRSRRRProof [EQUIVALENT, 488 ms] (2) RelTRS (3) RelTRSRRRProof [EQUIVALENT, 336 ms] (4) RelTRS (5) RelTRSRRRProof [EQUIVALENT, 20 ms] (6) RelTRS (7) RelTRSRRRProof [EQUIVALENT, 3 ms] (8) RelTRS (9) RIsEmptyProof [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: a(a(c(x1))) -> c(c(b(x1))) b(b(b(x1))) -> a(b(b(x1))) The relative TRS consists of the following S rules: b(b(a(x1))) -> a(a(c(x1))) c(c(b(x1))) -> b(b(c(x1))) b(b(a(x1))) -> a(b(b(x1))) a(b(a(x1))) -> c(b(a(x1))) ---------------------------------------- (1) RelTRSRRRProof (EQUIVALENT) We used the following monotonic ordering for rule removal: Matrix interpretation [MATRO] to (N^2, +, *, >=, >) : <<< POL(a(x_1)) = [[0], [1]] + [[1, 1], [1, 0]] * x_1 >>> <<< POL(c(x_1)) = [[0], [0]] + [[1, 1], [1, 0]] * x_1 >>> <<< POL(b(x_1)) = [[0], [1]] + [[1, 1], [1, 0]] * x_1 >>> With this ordering the following rules can be removed [MATRO] because they are oriented strictly: Rules from R: none Rules from S: b(b(a(x1))) -> a(a(c(x1))) ---------------------------------------- (2) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: a(a(c(x1))) -> c(c(b(x1))) b(b(b(x1))) -> a(b(b(x1))) The relative TRS consists of the following S rules: c(c(b(x1))) -> b(b(c(x1))) b(b(a(x1))) -> a(b(b(x1))) a(b(a(x1))) -> c(b(a(x1))) ---------------------------------------- (3) RelTRSRRRProof (EQUIVALENT) We used the following monotonic ordering for rule removal: Matrix interpretation [MATRO] to (N^2, +, *, >=, >) : <<< POL(a(x_1)) = [[1], [0]] + [[1, 1], [1, 0]] * x_1 >>> <<< POL(c(x_1)) = [[0], [0]] + [[1, 1], [1, 0]] * x_1 >>> <<< POL(b(x_1)) = [[1], [0]] + [[1, 1], [1, 0]] * x_1 >>> With this ordering the following rules can be removed [MATRO] because they are oriented strictly: Rules from R: none Rules from S: a(b(a(x1))) -> c(b(a(x1))) ---------------------------------------- (4) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: a(a(c(x1))) -> c(c(b(x1))) b(b(b(x1))) -> a(b(b(x1))) The relative TRS consists of the following S rules: c(c(b(x1))) -> b(b(c(x1))) b(b(a(x1))) -> a(b(b(x1))) ---------------------------------------- (5) RelTRSRRRProof (EQUIVALENT) We used the following monotonic ordering for rule removal: Matrix interpretation [MATRO] to (N^2, +, *, >=, >) : <<< POL(a(x_1)) = [[0], [0]] + [[1, 1], [0, 2]] * x_1 >>> <<< POL(c(x_1)) = [[0], [1]] + [[2, 0], [2, 0]] * x_1 >>> <<< POL(b(x_1)) = [[0], [0]] + [[2, 0], [0, 0]] * x_1 >>> With this ordering the following rules can be removed [MATRO] because they are oriented strictly: Rules from R: a(a(c(x1))) -> c(c(b(x1))) Rules from S: none ---------------------------------------- (6) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: b(b(b(x1))) -> a(b(b(x1))) The relative TRS consists of the following S rules: c(c(b(x1))) -> b(b(c(x1))) b(b(a(x1))) -> a(b(b(x1))) ---------------------------------------- (7) RelTRSRRRProof (EQUIVALENT) We used the following monotonic ordering for rule removal: Knuth-Bendix order [KBO] with precedence:b_1 > c_1 > a_1 and weight map: b_1=1 a_1=1 c_1=2 The variable weight is 1With this ordering the following rules can be removed [MATRO] because they are oriented strictly: Rules from R: b(b(b(x1))) -> a(b(b(x1))) Rules from S: c(c(b(x1))) -> b(b(c(x1))) b(b(a(x1))) -> a(b(b(x1))) ---------------------------------------- (8) Obligation: Relative term rewrite system: R is empty. S is empty. ---------------------------------------- (9) RIsEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (10) YES